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bearhunter [10]
3 years ago
9

Passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to ?

Mathematics
2 answers:
Ilya [14]3 years ago
8 0

Answer:

The answer is C. -5x - 3y = 0

ratelena [41]3 years ago
5 0

ANSWER

- 5x  - 3y = 0

EXPLANATION

The line that passes through the origin has equation of the form:

y=mx

Where m is the slope.

Since the line is parallel to the line through A(-3, 0) and B(-6, 5), they have the same slope.

The slope is given by:

m =  \frac{y_2-y_1}{x_2-x_1}

m =  \frac{5 - 0}{ - 6 -  - 3}  =  -  \frac{5}{3}

Hence the required equation is:

y =   - \frac{5}{3} x

Multiply through by 3,

3y =  - 5x

In standard form, the equation is

- 5x  - 3y = 0

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Giving the following information:

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\cos\Theta=\dfrac{\bold{v_1}\circ\bold{v_2}}{||\bold{v_1}||\cdot||\bold{v_2}||}=\dfrac{-7}{5\cdot\sqrt{29}}\\\\\\&#10;\cos\Theta=-\dfrac{7}{5\sqrt{29}}\quad\implies\quad\Theta=\arccos\left(-\dfrac{7}{5\sqrt{29}}\right)\\\\\\\boxed{\Theta\approx105,1^\circ}
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