Answer:
D. (0,0)
Step-by-step explanation:
F(x)=6x
0=6x
x=0
The conditions are suitable to be modelled using a binomial distribution.
p=0.43
n=15
x=5
P(x=5)
=C(15,5)*0.43^5*(1-0.43)^(15-5)
=15!/(5!(15-5)!)*0.43^5*(1-0.43)^(15-5)
=3003*0.0147008*0.003620333
=0.1598
Answer:
the blank contains the term 2⁴²
Step-by-step explanation:
The Equation given in the question (2²¹ − 1)(2²¹ +1)
on evaluating the above expression,
we have
⇒ 2²¹ × (2²¹ + 1 ) -1 × (2²¹ + 1)
or
⇒ 2²¹⁺²¹ + 2²¹ - 2²¹ - 1² (using the property Xᵃ × Xᵇ = Xᵃ⁺ᵇ)
or
⇒ 2⁴² + 0 - 1
or
⇒ 2⁴² - 1
on comparing the result with LHS, we have
therefore,
the blank containing the term 2⁴²
Answer:
If we consider real numbers, there is no solution.
If we take into account imaginary numbers, there are 2 solutions. ![x=8i, -8i](https://tex.z-dn.net/?f=x%3D8i%2C%20-8i)
Step-by-step explanation:
We can take 64 to the other side and then take the square root.
Thus, we have:
![x^2+64=0\\x^2=-64\\x=\sqrt{-64}](https://tex.z-dn.net/?f=x%5E2%2B64%3D0%5C%5Cx%5E2%3D-64%5C%5Cx%3D%5Csqrt%7B-64%7D)
<u>We CANNOT take the square root of a negative number, so there is </u><u>no solution.</u>
<em>BUT, if we take into account Imaginary Numbers</em>, we can solve:
![x=\sqrt{-64} \\x=\sqrt{(-1)(64)} \\x=\sqrt{-1} \sqrt{64} \\x=8i](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B-64%7D%20%5C%5Cx%3D%5Csqrt%7B%28-1%29%2864%29%7D%20%5C%5Cx%3D%5Csqrt%7B-1%7D%20%5Csqrt%7B64%7D%20%5C%5Cx%3D8i)
Where ![\sqrt{-1} =i](https://tex.z-dn.net/?f=%5Csqrt%7B-1%7D%20%3Di)
AND, we can take the positive and negative versions of 8i, since squaring would take it back to original.
So the answer would be 8i and -8i