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3 years ago

If 3 drinks cost $9.00, how much will 5 drinks cost

2 answers:

8 0

Hi there!

If 3 drinks cost $9 then what we have to do is divide $9 by 3, which gives us - $3

Therefore 1 drink cost $3, meaning all we will have to do is multiply 5 by $3, which will give us - $15

The answer is - $15

Hope this helped you!

~Alexa

zysi [14]3 years ago

4 0

It will be $15 dollars for 5 drinks

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Introduction to Functions quiz answers?

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3 years ago

How to solve this problem

Slav-nsk [51]

Answer:

8.95

Step-by-step explanation:

here we are going to use pythagoras theorem

a² +b² =c²

the vertical can be taken as a and horizontal as b

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this is the same as

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3 0

3 years ago

For the following system, determine if a steady state exists and give the steady state value. The population of a colony of squi

Anettt [7]

Answer:

Option A)

$\displaystyle\lim_{t\to\infty}~p(t) = k$

Step-by-step explanation:

We are given the following on the question:

$p(t) =\displaystyle\frac{4000}{4+e^{-0.02t}}$

where p(t) is the population of a colony.

For steady state solution we evaluate:

$\displaystyle\lim_{t\to\infty}~p(t)\\\\= \lim_{x\to\infty} \frac{4000}{4+e^{-0.02t}}\\\\=\frac{4000}{4+e^{-\infty}}\\\\=\frac{4000}{4}\\\\= 1000$

Thus, the steady state solution is a constant, k = 1000.

Thus, the correct answer is

Option A)

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8 0

3 years ago

PLEASE HELP IM BEGGING YOU ITS DUE IN 15 MIN ILL GIVE BRAINEST AND PTS

lys-0071 [83]

answer:

you just have to shrink it down to 4cm then to 2cm

i wish i could help out more, but i would need to have access to the form

hopefully, this helps anyhow :)

good luck

have a great day !!

4 0

3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago