Solve the system of equations.
12x + 3y = 12
-6x +y = -26
A) (-3,9)
B (-6, -9)
© (-3,8)
D (3, -8)
12x + 3y = 12
2(-6x +y = -26)
12x + 3y = 12
-12x + 2y = -52
—-now x cancels out
5y/5 = -40/5
y = -8
The answer should be D. Let me know if you got it right.
Answer: m= -2
7(m+5) = 21
7m + 35 = 21
-35. -35
7m = -14
————-
7. 7
m = -2
Answer:
(x - 3)² = 10
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
x² = 6x + 1
<u>Step 2: Rewrite</u>
- Subtract 6x on both sides: x² - 6x = 1
- Complete the Square: x² - 6x + 9 = 1 + 9
- Factor: (x - 3)² = 10
Answer:
x = 4, y = 2
Step-by-step explanation:
Start by multiplying the first equation by 2:
2x + 2y = 12 --> 4x + 4y = 24
Subtract the second from the first:
4x + 4y = 24
- 5x + 4y = 28
4x - 5x = -x
4y = 4y = 0
24 - 28 = -4
so you end with -x + 0 = -4
Solve for x to get x = 4
Plug x = 4 back into 2x + 2y = 12 to find y.
2(4) + 2y = 12
8 + 2y = 12
2y = 4
y = 2