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MAXImum [283]
3 years ago
9

BRAINLIEST ANSWER (please do it right)

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

55 performances

Step-by-step explanation:

The first equation will be the total cost. The total cost has $88,000 already and then $5,900 is added with each performance. So the equation would be 88,000+5,900x because x will represent the number of performances.

y = 88,000 + 5,900x

The next equation will be how much the performances earn. If they earn $7,500 with each performance then the equation will be 7,500x, with x representing the number of performances

y = 7,500x

Now set the equations equal to each other and solve for x

7,500x = 88,000 + 5,900x

1,600x = 88,000

x = 55

They need to have 55 performances for the cost and the revenue to break even.

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Step-by-step explanation:

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Solve: 2/3x - 3/4 = 5 + 5/6x
Slav-nsk [51]

Answer:

\large\boxed{x=-\dfrac{69}{2}\to x=-34\dfrac{1}{2}\to x=-34.5}

Step-by-step explanation:

\dfrac{2}{3}x-\dfrac{3}{4}=5+\dfrac{5}{6}x\qquad\text{multiply both sides by LCD = 12}\\\\12\!\!\!\!\!\diagup^4\cdot\dfrac{2}{3\!\!\!\!\diagup_1}x-12\!\!\!\!\!\diagup^3\cdot\dfrac{3}{4\!\!\!\diagup_1}=(12)(5)+12\!\!\!\!\!\diagup^2\cdot\dfrac{5}{6\!\!\!\diagup_1}x\\\\(4)(2x)-(3)(3)=60+(2)(5x)\\\\8x-9=60+10x\qquad\text{add 9 to both sides}\\\\8x-9+9=60+9+10x\\\\8x=69+10x\qquad\text{subtract}\ 10x\ \text{from both sides}\\\\8x-10x=69+10x-10x\\\\-2x=69\qquad\text{divide both sides by (-2)}\\\\x=-\dfrac{69}{2}

7 0
4 years ago
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ad-work [718]
It's not difficult to compute the values of A and B directly:

A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}
A=\tan^{-1}(\sin\theta)-\dfrac\pi4

B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt
B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}
B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2

Let's assume 0, so that |\csc\theta|=\csc\theta.

Now,

\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}
\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}
\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)
\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in A and B.
3 0
3 years ago
Calculate the value of x if 2x/3=8/5
Cloud [144]

Answer:

12/5 or 2⅖

Step-by-step explanation:

2x/3 = 8/5

2x = 3 × 8/5

2x = 24/5

x = 24/5 ÷ 2

x = 12/5

Or 2⅖

5 0
3 years ago
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