Answer:
About 48 members would be expected to say that dues be raised
Step-by-step explanation:
Here, we shall be using a case of a representative sampling to determine the actual.
Out of the 100 selected members, 6 said the dues should be raised;
This represents a percentage of 6/100 = 6%
So out of the 800, the expected number of members that would ask for a dues raising will be;
6/100 * 800 = 48

but anyway, the numerator will give the angles, and θ is just half of each

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025
so the angle is 355.975°
now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°
and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
The angle that the minute and hour hands make when they are at 8:00 is obtuse
The volume would be 5 because in order to find volume you need to divide mass over density. V=m/d