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AnnyKZ [126]
3 years ago
8

How can you move just one number to a different

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer:

Remove 9 from triangle B to A

Step-by-step explanation:

Given

Three Triangles

A: 1,2,3

B: 7,8,9

C: 4,5,6

Required

Make their sum equal

First, we need to calculate the sum in each triangles;

A = 1 + 2 + 3

A = 6

B = 7 + 8 + 9

B = 24

C = 4 + 5 + 6

C = 15

Remove 9 from triangle B to A

A = 6 + 9

A = 15

B = 24 - 9

B = 15

At this point, we have:

A = 15     B = 15     C = 15

<em>Hence, the solution is to remove 9 from B to A</em>

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Listed below are the ACT scores of 40 randomly selected students at a major university. (Use technology if you wish, Excel) 18 1
tiny-mole [99]

Answer:

A) See the picture

B) 14

C) 45%

Step-by-step explanation:

A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable

B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution

Pc1 = 100*(4/40) = 10

Pc2 = 100*(4/40) = 10

Pc3 = 100*(3/40) = 7.5

Pc4 = 100*(11/40) = 27.5

Pc5 = 100*(5/40) = 12.5

Pc6 = 100*(4/40) = 10

Pc7 = 100*(7/40) = 17.5

Pc8 = 100*(2/40) = 5

Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%

Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.

C) Scores equal to or greater than 20 are from class 8 to class 5

Pc8 + Pc7 + Pc6 + Pc5 = 45%

5 0
4 years ago
Solve. -5x - 3y = -20
patriot [66]

Answer:

it is a are b but it could be c

6 0
4 years ago
Find the second, fourth, and eleventh terms of the
tekilochka [14]

Answer:

The second term is -6 , the fourth term is 0 , the eleventh term is 21

Step-by-step explanation:

* Lets revise the explicit formula

- An explicit formula will create a sequence using n, the number

 position of each term.

- If you can find an explicit formula for a sequence, you will be able

 to quickly and easily find any term in the sequence by replacing

 n with the number of the term you want

- It defines the sequence as a formula in terms of n.

* Now lets solve the problem

- The formula of the sequence is A(n) = -9 + (n - 1)(3)

- A(n) is any term in the sequence

- n is the position of the number

- To find the second term put n = 2

∵ n = 2

∴ A(2) = -9 + (2 - 1)(3) = -9 + (1)(3) = -9 + 3 = -6

* The second term is -6

- To find the fourth term put n = 4

∵ n = 4

∴ A(4) = -9 + (4 - 1)(3) = -9 + (3)(3) = -9 + 9 = 0

* The fourth term is 0

- To find the eleventh term put n = 11

∵ n = 11

∴ A(11) = -9 + (11 - 1)(3) = -9 + (10)(3) = -9 + 30 = 21

* The eleventh term is 21

5 0
3 years ago
Read 2 more answers
the\ function\ h\left(x\right)=\frac{1}{2}\left(x+3\right)^{2}+2.How\ is\ the\ graph\ of\ h\left(x\right)\ t\ r\ a\ nslated\ \ f
Feliz [49]

The function h(x) is vertically stretched by a factor of \frac{1}{2} and is shifted 3 units to the left and shifted 2 units up.

Explanation:

The parent function is f(x)=x^{2}

The translated function is h(x)=\frac{1}{2}(x+3)^{2}+2

By using the function transformation rules, the translated function h(x) is stretched vertically by a factor of \frac{1}{2}

Also, from the function transformation rules, we know that,  $f(x+b)$ shifts the function b units to the left.

Thus, the translated function h(x) is shifted 3 units to the left.

By using the function transformation rules, we know that,  $f(x)+b$ shifts the function b units upward.

Thus, the translated function h(x) is shifted 2 units upwards.

Thus, the translated function h(x) is vertically stretched by a factor of \frac{1}{2} and is shifted 3 units to the left and shifted 2 units up.

8 0
4 years ago
PLEASE HELP ME AS SOON AS POSSIBLE!!!!!!!!!!!!!!!!!!!!!!!!
Anna007 [38]
Hi there.
They are basically asking how you could change the graph in a way so that the change in wins isn't as noticeable. This can be done by starting at zero number of wins on the y-axis.

5 0
3 years ago
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