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V125BC [204]
3 years ago
11

Easy how many factors does 270 have

Mathematics
2 answers:
Mashutka [201]3 years ago
7 0

Hello from MrBillDoesMath!

Answer:

16

Discussion:

The factors are (base on fact that 270 = 2 * 3^3 * 5)

1 , 2 , 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270

Thank you,

MrB

Vlad [161]3 years ago
6 0

Answer:

16

Step-by-step explanation:

Answer : 1,2,3,5,6,9,10,15,18,27,30,45,54,90,135,270

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Assume each figure shown has the same orientation.
marysya [2.9K]

Answer: square 4

Step-by-Step explanation:

Translation (x+5, y-3) is the movement of LMNP five units to the right and three units down

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3 years ago
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HELP ASAP BRAINLIEST FOR FIRST CORRECT ANSWER In triangle ABC, m∠A=(5x−10)∘, m∠B=(12x)∘, and the exterior angle at C is (16x)∘.
kirill [66]

Answer:

160

Step-by-step explanation:

5x-10+12x=16x

17x-16x=10

x= 10

exterior angle at C = 16x= 16×10 = 160°

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3 years ago
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Patricia is 5 years older than Wyatt. The sum of their ages is 61. How old are Patricia and Wyatt?
baherus [9]

Answer

w+(w+5)=61

Step-by-step explanation:

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3 years ago
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The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
PLEASE SOMEONE HELP ME
kow [346]

Answer:

1/5 is not greater than 2/7 because 1/5 = 7/35 and 2/7 = 10/35.

7 0
3 years ago
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