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3 years ago

What is 4X -3+ 2X plus one minus X +8

Mathematics

2 answers:

garri49 [273]3 years ago

5 0

Answer:

5x + 6

Step-by-step explanation:

4x - 3 + 2x + 1 - x + 8

= 4x + 2x - x -3 + 1 +8

= 5x + 6

beks73 [17]3 years ago

3 0

5x+6
4x+2x=6x 6x-1x=5x
-3+1=-2+8=6
5x+6= 5x+6

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Answer:

$\lambda=8,\ \lambda=-5$

Step-by-step explanation:

<u>Eigenvalues of a Matrix</u>

Given a matrix A, the eigenvalues of A, called $\lambda$ are scalars who comply with the relation:

$det(A-\lambda I)=0$

Where I is the identity matrix

$I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

The matrix is given as

$A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]$

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$det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0$

Expanding the determinant

$det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0$

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The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.

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Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

where,

$r_1$ = radius of sphere = $\frac{Diamtere}{2}=\frac{8cm}{2}=4cm$

$r_2$ = radius of cylindrical wire = $\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm$

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

$\frac{4}{3}\times r_1^3=r_2^2h$

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Therefore, the length of the wire is, 8533 cm

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