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Gelneren [198K]
3 years ago
15

Fill in the bubble next to all the doubles facts you could use to fined the sum of 4+5

Mathematics
2 answers:
dedylja [7]3 years ago
8 0
There is no image...

hjlf3 years ago
3 0
Yeah there's no picture there that I can see
You might be interested in
If the two consecutive numbers is 23 , find them​
Iteru [2.4K]
<h2>(☞^o^) ☞</h2><h2>Here's your answer </h2>

Step-by-step explanation:

Let the two consecutive natural numbers be x and x+1

Now, according to the problem

x+(x+1)=23

⇒ 2x+1=23

⇒ 2x=23−1

⇒ 2x=22

⇒ x=22÷2=11

The one number is 11

The next number is x+1=11+1=12

Hence the numbers are 11 and 12.

Be my Friend...

5 0
2 years ago
Anyone know what the answer is???(sorry if it’s unclear)
Sergio [31]

The laws of exponents I will be using are:

(x^y)^z = x^{yz}, and x^y \cdot x^z = x^{y+z}.

For the first part, (15^3)^3 \cdot 15^{-6} = 15^9 \cdot 15^{-6} = 15^3.

For the second part, 15 \cdot (15^3)^2 \cdot (15^{-5})^2 = 15 \cdot (15^6) \cdot (15^{-10}) = 15^{1+6-10} = 15^{-3} = \frac{1}{15^3}.

5 0
3 years ago
Awnser!!!! I need it answered now please!!!!! only number 7!!!!!​
Aliun [14]

Answer:

y= 2x - 4

Step-by-step explanation:

The y-intercept is 4 and the rise and run is 2/1

5 0
3 years ago
3 3/8 + 1 1/4 help meeeee pleaseee
Amanda [17]

Answer:

37/8 (fraction) or 4.625 (decimal) or 4 5/8 (mixed number)

Step-by-step explanation:

3 0
3 years ago
Which equation has exactly two real and two non real solutions?
tatiyna

Answer:

The first option x^4-21x^2-100=0.

Step-by-step explanation:

To have exactly 2 real and two non real solutions, the degree of the polynomial must be a degree 4. Degree is the highest exponent value in the polynomial and is also the number of solutions to the polynomial. This polynomial ha 2 real+2 non real= 4 solutions and must be x^4. This eliminates the bottom two solutions.

In order to have two real and two non real solutions, the polynomial must factor. If it factors all the way like

x^4-100x^2=0\\x^2(x^2-100)=0\\x^2(x-10)(x+10)=0\\\\x^2=0\\x-10=0\\x+10=0

This means x=0, 10, -10 are real solutions to the polynomial. It has no non real solutions. This eliminates this answer choice.

Only answer choice 1 meets the requirement.

5 0
4 years ago
Read 2 more answers
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