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e-lub [12.9K]
3 years ago
15

I have 3 red jawbreakers 2 green 5 orange jawbreakers and 1 purple jaw breaker which color of jawbreaker can be represented as a

unit fraction of the bag of jawbreakers
Mathematics
1 answer:
Sonbull [250]3 years ago
6 0
2 green jawbreakers
-
⚯⚯
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A father is now twice as old as his son. If the sum of their ages ten years ago was fifty two, how old are they today?​
Oliga [24]

Answer:

24 and 48

Today, the son is 24 years old, and the father is 48 years old.  

Step-by-step explanation:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

The father is 2 times his son's age.

2x

= 2(24)

= 48

So, the son is 24 and the father is 48.

10 years ago, son was 14 and father was 38, if added, this adds up to 52, so we know our calculations are correct.

3 0
3 years ago
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Determine the Probability: P(B^c)
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3 years ago
For the inverse variation equation p=8/V<br> what is the value of Vwhen p=1/2?
NISA [10]

Answer:

v = 16

Step-by-step explanation:

p = 8/v and p = 1/2.  Equating these two, we get 8/v = 1/2.

Inverting both sides, we get v/8 = 2.

Find the vaue of v by multiplying both sides by 8:  v = 16

3 0
2 years ago
How do you know that 21 over 30 is greater than 2 over 3
Bond [772]
The problem deals with fractions comparison, lets do it:
21/30 > 2/3
we begin solving:
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21 > 2*10
<span>21 > 20
</span>therefore the proposed inequality is true, <span>21/30 > 2/3

You can solve as well getting same denominator for both fractions and comparing directly, in this case we need to get 2/3 to be divided by 30:
2/3 = (10/10)(2/3) = 20/30
So we have:
</span><span>21/30 > 2/3
</span>which is equal to:
<span>21/30 > 20/30
</span>and we compare directly because both fractions are divided by the same number, and we can see that the inequality is true.
7 0
3 years ago
Give the slope-intercept form of the equation of the line that is perpendicular to –7x – 8y = 12 and contains P(–3, 1)
Usimov [2.4K]
Answer is b.  :)     :)       :)      


4 0
3 years ago
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