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Greeley [361]
2 years ago
6

A desk drawer is shaped like a rectangular prism. The height of the drawer is 7 inches. The bottom of the drawer has an area of

210 square inches.
Mathematics
1 answer:
NISA [10]2 years ago
4 0

Answer:

We know the volume formula of rectangular prism is:

Volume = Length × Width × Height

We are given:

Volume = 1428 in³

Height = 6 in

Length = 17 in

Width = p

Apply the formula!

1428 = 6 × 17 × p

1428 = 102p

Divide by 102 on either side to isolate p

p = 14  

The width is 14 inches

Step-by-step explanation:

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PLS HELP TIMED QUIZ The size of a television screen is given as the length of the diagonal. If a television is advertised as hav
grin007 [14]

Answer:

D.24

Pythagorean states:

hypotenuse^2 = side1^2 + side2^2

30^2 = 18^2 + side2^2

side2^2 = 30^2 - 18^2

side2^2 = 900 - 324

side2^2 = 576

side2 = sqr root 576

side2 = 24

Source: http://www.1728.org/pythgorn.htm

Step-by-step explanation:

5 0
3 years ago
Which is a solution to the inequality y > 2 + 9x? Select all that apply.
creativ13 [48]
I know that’s a should be one of them
4 0
3 years ago
Could anyone help me? this is hard i dont understand
emmainna [20.7K]

Answer:

can you please give me an example?

i will help you but give me your teacher's example

Step-by-step explanation:

let me know if it's done

3 0
2 years ago
Evaluate the function for x = 2,3,4<br> F(x) =2x-7-3
laila [671]

Answer:

below in bold

Step-by-step explanation:

f(x) = 2x - 7 - 3

~Combine like terms

f(x) = 2x - 10

When x = 2...

f(x) = 2(2) - 10

f(x) = 4 - 10

f(x) = -6

When x = 3...

f(x) = 2(3) - 10

f(x) = 6 - 10

f(x) = -4

When x = 4...

f(x) = 2(4) - 10

f(x) = 8 - 10

f(x) = -2

Best of Luck!

8 0
3 years ago
Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360
Natasha2012 [34]

\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]

\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

   \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]

5 0
3 years ago
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