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Westkost [7]
3 years ago
11

ASAP Please help

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

The center is at ( (-1, -2) and the radius is 5.

Step-by-step explanation:

X^2 + 2X + Y^2 + 4Y = 20

Complete the square on the x and y terms.

(x + 1)^2 -1 + (y + 2)^2 - 4 = 20

(x + 1)^2 + ( y + 2)^2 = 25  Comparing this with the standard form:

(x - h)^2 + (y - k)^2 = r^2

- the center is at ( (-1, -2) and thr radius is 5.

Naya [18.7K]3 years ago
5 0
Center is (-1,-2) and radius is 5
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Answer:6/4

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2 years ago
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Please help if you can!!!!
storchak [24]

Answer:Well, I don't know what you got so I can't tell you if it is right.

If it works in both equations, it depends of whether your equations are set up correctly.

Here is how I would do this problem.

Let x = no. of hot dogs,y = number of sodas.

First equation is just about the number of things.

x + y = 15

Second equation is about the cost of things.

1.5 x + .75 y = 18

solve x+y = 15 for y  y = 15-x    substitute into second equation

1.5x + .75(15 - x) = 18    

You should get the correct answer for number of hot dogs if you solve this correctly.  Put your answer in the x + y =15 equation to get y.  Then put both x and y into the cost equation and check your answer.

Hope this helps.

Step-by-step explanation:

5 0
2 years ago
Yessenia is making cookies. the recipe calls for her to use 2/3 cup of white sugar and 1/2 cup of brown sugar. how many cups of
ANTONII [103]

Answer:

7/6

Hope this helps

8 0
3 years ago
3x^2-12x-21=0 solve by completing the square
morpeh [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

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sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
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