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AveGali [126]
3 years ago
12

Design a class called NumDays. The class’s purpose is to store a value that represents a number of work hours and convert it to

a number of days. For example, 8 hours would be converted to 1 day, 12 hours would be converted to 1.5 days, and 18 hours would be converted to 2.25 days. The class should have a constructor that accepts a number of hours, as well as member functions for storing and retrieving the hours and days. The class should also have the following overloaded operators:
+ addition operator: When two NumDays objects are added together, the overloaded + operator should return the sum of the two objects hours members.
-subtraction operator: When one NumDays object is subtracted from another, the overloaded- operator should return the difference of the two objects hours members.
++ prefix and postfix increment operators. These operators should increment the number of hours stored in that object. When incremented, the number of days should automatically be recalculated.
-- Prefix and postfix decrement operators. These operators should decrement the number of hours stored in that object. When decremented, the number of days should automatically be recalculated.
Computers and Technology
1 answer:
Afina-wow [57]3 years ago
3 0

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

class NumDays{

int hours;

float day;

public:

NumDays()

{

hours=0;

day=0.0;

};

NumDays(int h)

{

hours=h;

day=float(h/8.0);

};

int getHour()

{

return hours;

}

float getDay()

{

return day;

}

NumDays operator +(NumDays obj)

{

int h=getHour()+obj.getHour();

NumDays temp(h);

return temp;

}

NumDays operator -(NumDays obj)

{

int h=getHour()-obj.getHour();

NumDays temp(h);

return temp;

}

const NumDays& operator++() //prefix

{

++hours;

day=float(hours/8.0);

return *this;

}

const NumDays& operator--() //prefix

{

--hours;

day=float(hours/8.0);

return *this;

}

const NumDays operator++(int) //postfix

{

NumDays temp(*this);

++hours;

day=float(hours/8.0);

return temp;

}

const NumDays operator--(int) //postfix

{

NumDays temp(*this);

--hours;

day=float(hours/8.0);

return temp;

}

};

int main()

{

NumDays obj(2),obj2(10),obj3,obj4;

obj3=obj2-obj;

cout<<"'obj3=obj2-obj'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj3=obj+obj2;

cout<<"'obj3=obj+obj2'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj4=obj3++;

cout<<"'obj4=obj3++' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=++obj3;

cout<<"'obj4=++obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=obj3--;

cout<<"'obj4=obj3--' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=--obj3;

cout<<"'obj4=--obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

};

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How to write a function that counts the letters in a string in C?
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Answer:

Here is the C function that counts the letters in a string:

int LetterCount(char string[]){  //function to count letters in a string passed as parameter

 string[100];  // char type string with size 100

  int i, letters;  // letter variable stores the count for no. of letters in string

   i = letters = 0;  //initialize variables i and letters to 0

  while (string[i] != '\0')  { // loop iterates through the entire string until end of string is reached

    if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  { // if condition checks the letters in the string

     letters++;    }  // increments 1 to the count of letters variable each time a letter is found in the string

    i++;  }  //increments value of i to move one character forward in string

   printf("Number of Letters in this String = %d", letters);   // displays the number of letters in the string

   return 0; }                              

Explanation:

Here the question means that the function should count the letters in a string. So the letters are the alphabets from a to z and A to Z.

Here is the complete program:

#include <stdio.h>   // to use input output functions

int LetterCount(char string[]){  // method that takes a character string as parameter and counts the letters in the string

string[100];  

int i, letters;

i = letters = 0;

while (string[i] != '\0')   {

 if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z'))

   {letters++;  }

   i++; }

   printf("Number of Alphabets in this String = %d", letters);  

   return 0;}  

int main(){  // start of main function

  char string[100];  //declares a char array of string

   printf("Please Enter a String : ");   //prompts user to enter a string

  fgets(string,100,stdin);  //get the input string from user

   LetterCount(string); } // calls method to count letters in input string

I will explain this function with an example

Lets suppose the user input "abc3" string

string[100] = "abc3"

Now the function has a while loop that while (string[i] != '\0')  that checks if string character at i-th position is not '\0' which represents the end of the character string. As value of i = 0 so this means i is positioned at the first character of array i.e. 'a'

At first iteration:

i = 0

letter = 0

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )   if condition checks if the character at i-th position of string is a letter. As the character at 0-th position of string is 'a' which is a letter so this condition evaluates to true. So the statement letter++ inside if condition executes which increments the letter variable to 1. So the value of letter becomes 1. Next statement i++ increments the value of i to 1. So i becomes 1. Hence:

i = 1

letter = 1

At second iteration:

i = 1

letter = 1

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  

if condition checks if the character at i-th position of string is a letter. As the character at 1st position of string is 'b' which is a letter so this condition evaluates to true. So the statements letter++ inside if condition and i++ executes which increments these variables to 1. Hence:

i = 2

letter = 2

At third iteration:

i = 2

letter = 2

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  

if condition checks if the character at i-th position of string is a letter. As the character at 2nd position of string is 'c' which is a letter so this condition evaluates to true. So the statements letter++ inside if condition and i++ executes which increments these variables to 1. Hence:

i = 3

letter = 3

At fourth iteration:

i = 3

letter = 3

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  

if condition checks if the character at i-th position of string is a letter. As the character at 3rd position of string is '3' which is not a letter but a digit so this condition evaluates to false. So the statement letter++ inside if condition does not execute. Now i++ executes which increments this variable to 1. Hence:

i = 4

letter = 3

Now the loop breaks because while (string[i] != '\0') condition valuates to false as it reaches the end of the string.

So the statement: printf("\n Number of Letters in this String = %d", letters); executes which prints the value of letters on the output screen. Hence the output is:

Number of Letters in this String = 3

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Sliva [168]
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We need an equals method for the Dog class. It needs to give back to the caller a boolean value indicating whether another objec
Nadusha1986 [10]

Answer and Explanation:

Using Javascript:

Class Dog{

var healthScores=[];

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}

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If(new Dog.name===this.name,new Dog.age===this.age, new Dog.healthScores===this.healthScores){return true;

}

else{

console.log("objects are not equal");

}

}

}

To call the method checkObject:

var Tesa = new Dog(Tes,1,[45,46,82]);

var Bingo = new Dog(bing,2,[43,46,82]);

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Note: we have used ES6(latest version of Javascript) where we passed the healthScore parameter(which is an array) to our constructor using the spread operator.

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muminat

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Hope this helps Have a good day

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