The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
Answer:
12.34
Step-by-step explanation:
For divide by the number then you get the answer
Answer:
1.
Tan 45=√2/n
n=√2
again
sin 45=√2/m
m=2
answer:<u> </u><u>m</u><u>=</u><u>2</u><u>,</u><u>n</u><u>=</u><u>√</u><u>2</u>
<u>2</u><u>.</u>
sin 45=x/3
x=3/√2=3√2/2
y=3√2/2
<u>a</u><u>n</u><u>s</u><u>:</u><u>x</u><u>=</u><u>3√2/2</u><u>,</u><u>y</u><u>=</u><u>3√2/</u><u>3</u>
<u>3</u><u>.</u>
sin 45=a/4
a=4/√2
b=4/√2
ans:<u>a</u><u>=</u><u>4</u><u>/</u><u>√</u><u>2</u><u>,</u><u>b</u><u>=</u><u>4</u><u>/</u><u>√</u><u>2</u>
4.
b=4 base sides of isosceles triangle
sin 45=4/a
a=4√2
ans:<u>a</u><u>=</u><u>4</u><u>√</u><u>2</u><u> </u><u>and</u><u> </u><u>b</u><u>=</u><u>4</u>
Answer: 3x one unit to the left and four units up.
Step-by-step explanation: I took the quiz and made an 100 !!!! :)
Answer:
<u>x<6/7</u>
Step-by-step explanation:
7x/3 < 2
7x < 6
<u>x < 6/7</u>
<u></u>
<h3><u>
If you need to ask any questions, please let me know.</u></h3>
