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Mkey [24]
3 years ago
10

Find two numbers whose difference is 164 and whose product is a minimum. (smaller number) (larger number)

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0
The lowest possible product would be -6724 given the numbers 82 and -82. 

We can find this by setting the first number as x + 164. The other number would have to be simply x since it has to have a 164 difference. 

Next we'll multiply the numbers together. 
x(x+164)
x^2 + 164x

Now we want to minimize this as much as possible, so we'll find the vertex of this quadratic graph. You can do this by finding the x value as -b/2a, where b is the number attached to x and a is the number attached to x^2

-b/2a = -164/2(1) = -164/2 = -82

So we know one of the values is -82. We can plug that into the equation to find the second. 

x + 164
-82 + 164 
82
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Answer:

x = -2.

Step-by-step explanation:

In this case, a is 1, b is 4 and c is 4.

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x = -2.

Hope this helps!

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Select all the expressions that are equivalent to -36x+54y−90.
CaHeK987 [17]

Answer:

b) -18(2x -3y + 5)

d) 18(-2x + 3y - 5)

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Step-by-step explanation:

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d) 18(-2x + 3y - 5) = -36x + 54y - 90 equal

e) -2(18x - 27y + 45) = -36x + 54y - 90 equal

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