Question

alt="\huge\boxed{PLEASE\;HELP!}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

$\boxed{y = - 1x + 2}.$

Step-by-step explanation:

$in \: order \: to \: solve \: the \: problem \: we \: invoke \\ \: the \:slope \: intercept \: form : \\ y = mx + c \\ lets \: get \: m \to \: \\ m= \frac{ y_{2} - y_{1} }{x_{2} -x_{1} } = \frac{2 - 0}{0 - ( - 2)} \\ m = \boxed{- 1}. \\to \: find \: c \: we : apply \to \\ y = mx + c...... \\ using \: any \: pair \: we \: can \: get \: c. \\ c = y - mx \\ c =2 - 1(0) \\ c = \boxed{2}. \\ hence \: the \: required \: equation \: is : \\ \boxed{y = - 1x + 2}.$

♨Rage♨

Answer 2

Answer:

y=1x+2

Step-by-step explanation:

do $y2-y1 / x2-x1$ to get m(slope)

y1=2

x1=0

y2=0

x2=-2

then do y=mx+b

1=m(slope)

2=b(y-intercept)

Hope this wasn't to confusing!

I hope this helps! :)