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3 years ago

5

The product of n, r and 21

1 answer:

Zinaida [17]3 years ago

7 0

I font understand wat ur asking

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ALGEBRA<br> EQUATION<br> PLEASE HELP ASAP<br><br> -3=12y-5(2y-7)

Dovator [93]

Simplify:

−3=12y−5(2y−7)

−3=12y+(−5)(2y)+(−5)(−7)(Distribute)

−3=12y+−10y+35

−3=(12y+−10y)+(35)(Combine Like Terms)

−3=2y+35

Flip the equation.

2y+35=−3

Subtract 35 from both sides.

2y+35−35=−3−35

2y=−38

Divide both sides by 2.

2y/2=−38/2

y=−19

3 0

3 years ago

Read 2 more answers

Solve the Equation |x-8|=16

choli [55]

|x-8| = 16
⇒ x-8= 16 or x-8= -16
⇒ x= 16+ 8 or x= -16+ 8
⇒ x= 24 or x= -8

Final answer: x= 24 or x= -8~

4 0

3 years ago

Read 2 more answers

Plz answer quickly !!!!

SVETLANKA909090 [29]

Im pretty sure: 18 units

8 0

3 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

as

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago

A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has

cluponka [151]

Answer:!!

Step-by-step explanation:!!

8 0

3 years ago