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svp [43]
3 years ago
5

The product of n, r and 21

Mathematics
1 answer:
Zinaida [17]3 years ago
7 0
I font understand wat ur asking
You might be interested in
I need help , I don’t understand this
marta [7]
#2. First, we factor each polynomial. Then, if any terms on both the top and the bottom of the fraction match, they cancel out. So... we do just that. You end up with:

\frac{x(x-4)}{(x+9)(x-4)}

Notice there's an (x-4) on both top and bottom. So they cancel out. That leaves us with your answer of \frac{x}{(x+9)}

#3. We do the same thing as above then multiply and simplify. In the interest of space, I'll cut straight to some simplification. 

\frac{2(x+2)^{3} }{6x(x+2)} ( \frac{5}{(x-2)^{2} } )

Now we start cancelling. For the first fraction, there are 3 (x+2)'s on top and 1 on the bottom so we will cancel out the one on the bottom and leave 2 (x+2)'s on top. There are no more polynomials to cancel out so now we multiply across:

\frac{10(x+2)^{2} }{6x(x-2)^{2} }

10 and 6 share a GCF of 2 so we divide both of those by 2. This leaves us with the final answer of:

\frac{5(x+2)^{2} }{3x(x-2)^{2} }

#4. This equation introduces division and because of it, we must flip the second fraction to make the division sign into a multiplication symbol. Again for space, I'll flip the fraction and simplify in one step. 

\frac{3(x+2)(x-2)}{(x+4)(x-2)} ( \frac{x+4}{6(x+3)})

Now we do our cancelling. First fraction has (x - 2) in the top and bottom. They're gone. The first fraction has a (x + 4) on the bottom and the second fraction has one on the top. Those will also cancel. This leaves you with:

\frac{3(x+2)}{6(x+3)}

3 and 6 share a GCF of 3 so we divide both numbers by this. This leaves you with your final answer:

\frac{x+2}{2(x+3)}

#5. We are adding so we first factor both fractions and see what we need to multiply by to make the denominators the same. I'll do the former first. (10 - x) and (x - 10) are not the same so we multiply the first equation (top and bottom) by (x - 10) and the second equation by (10 - x). Because they will now have the same denominator we can combine them already. This gives us:

\frac{(3+2x)(x-10)+(13+x)(10-x)}{(10-x)(x-10)}

Now we FOIL each to expand and then simplify by combining like terms. Again for space, I'm just showing the result of this; you end up with:

\frac{x^{2}-20x+100}{(10-x)(x-10)}

Now we factor the top. This gives you 2 (x - 10)'s on top and one on bottom. So we just leave one on the top and cancel the bottom one out. This leaves you with your answer:

\frac{x+10}{10-x}

#6. Same process for this one so I won't repeat. I'll just show the work.

\frac{3}{(x-3)(x+2)} +  \frac{2}{(x-3)(x-2)} becomes

\frac{3(x-2) + 2(x+2)}{(x-3)(x+2)(x-2)} which equals

\frac{3x - 6 + 2x + 4}{(x-3)(x+2)(x-2)} giving you the final answer

\frac{5x - 2}{(x-3)(x+2)(x-2)}

#7. For this question we find the least common denominator to make the denominators match. For 5, x, and 2x, the LCD is 10x. So we multiply top and bottom of each fraction by what would make the bottom equal 10x. This rewrites the fraction as:

\frac{3x}{5} ( \frac{2x}{2x}) * ( \frac{5}{x}( \frac{10}{10}) -  \frac{5}{2x} ( \frac{5}{5}))

Simplify to get:

\frac{3x}{5}  * ( \frac{25}{10x})

After simplifying again, you end up with your final answer: 

\frac{3}{2}




8 0
3 years ago
Solve the following Simultaneous equation<br>Using any suitable method<br> x+6y=2, 3x +2y =10​
uranmaximum [27]

Answer:

x = 0.5

y = -1/4 or -0.25

Step-by-step explanation:

x + 6y = 2

3x + 2y = 10

Multiply a number by any of the equations to get numbers of the same variable

3x + 18y = 6

3x + 2y = 10

3x - 3x = 0

NB: subtract evenly if u subtract down from top make sure u subtract down from top throughout

16y = -4

16y/16 = -4/16

y = -1/4 or -0.25

to find the x value, any where you see y u put in the y value(-0.25)

So u'll pick just one of the equations above

x + 6(0.25) = 2

x + 1.5 = 2

x = 1.5 + 2

x = 0.5

5 0
3 years ago
1 of 6 The length of each side of a square is 6.1 cm rounded to 1 decimal place. Write the error interval for the perimeter, p ,
arsen [322]

The error interval of the perimeter is 6.1 cm ≤ p < 6.15 cm

<h3>How to determine the error of interval?</h3>

The perimeter is given as:

P = 6.1 cm to 1 decimal place

The smallest number that can be approximated to 6.1 is 6.05, while the largest number is less than 6.15

This means that the interval is:

6.1 cm ≤ p < 6.15

Read more about error interval at:

brainly.com/question/16810055

#SPJ1

8 0
1 year ago
An equation of the line that passes through the given point and is parallel to the graph of the given equation
notsponge [240]

To construct the equations for these lines, we are going to use the point-slope formula, which is:

(y - y_1) = m(x - x_1)

  • m is the slope of the line
  • (x_1, y_1) is a point on the line

1)

In this case, our point is (2, -1) and our line has a slope of 5. (Remember that the line is parallel, meaning that it has the same slope as the given line. Since the line is in the y = mx + b format, we could easily pick out the slope m as being 5.)

Thus, we can "plug in" what we know into our formula to find the equation of our line:

(y + 1) = 5(x - 2)

(y + 1) = 5x - 10

y = 5x - 11


2)

We are going to do the same thing, except our point is now (0, -5) and our slope is now 9.

(y + 5) = 9(x - 0)

y = 9x - 5


Our equations are:

1) y = 5x - 11

2) y = 9x - 5

7 0
3 years ago
I need help PLEASE! :(
Sedaia [141]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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