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svp [43]
3 years ago
5

The product of n, r and 21

Mathematics
1 answer:
Zinaida [17]3 years ago
7 0
I font understand wat ur asking
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4×7.12 in distribitive property
bija089 [108]
The answer will be 28.48
3 0
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A bag contains 3 green marbles and 8 white marbles. Suppose a marble is randomly selected. What are the odds in favor of picking
KatRina [158]
It would be 7 out of 11 because there are 8 marbles and you only took out one white marble

4 0
3 years ago
Read 2 more answers
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
Find equation of a line through 5 -3 that is parallel to y=1/2x+3
xxTIMURxx [149]

Answer:

The equation of a line through (5 -3) that is parallel to y = 1/2 x+3 is

y = - 2 x  + 7

Step-by-step explanation:

Let us assume the slope of the line whose equation we need to find is m 1.

The line parallel to the needed line  is:   y=1/2x+3

Comparing it with the general form: y = m x + C

we get m 2 = 1/2

Now, as Line 1 is Perpendicular to Line 2.

⇒ m 1 x m 2  = -1

⇒ m 1 x ( 1/2)  = -1

⇒ m 1  = - 2

Also, the point son the line 1 is given as: (x,y)  = (5,-3)

Put the value of point and Slope in y = m x + C to find the value of Y- INTERCEPT.

we get: -3 = (-2) (5) +  C

or, C = -3 + 10 = 7

⇒ C = 7

The general line equation is given as:  y = m x + C

Substituting  the values of C and m, we get:

y = - 2 x  + 7

Hence, the equation of a line through 5 -3 that is parallel to y = 1/2 x+3 is

y = - 2 x  + 7

8 0
3 years ago
(5 + 42) ÷ 3 ● 6<br> I need the answer and Steps Plz
Alex
47/3 x6
Reduce
47x2
=
94
7 1
3 years ago
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