Question

How do you solve this?

Answer 1

Answer:

9(x + 3)

Step-by-step explanation:

$\dfrac{2x^2 + x - 15}{2x^2 - 11x - 21} \times (6x + 9) \div \dfrac{2x - 5}{3x - 21} =$

Change division into multiplication by reciprocal.

$= \dfrac{2x^2 + x - 15}{2x^2 - 11x - 21} \times (6x + 9) \times \dfrac{3x - 21}{2x - 5}$

Factor every polynomial.

$= \dfrac{(2x - 5)(x + 3)}{(x - 7)(2x + 3)} \times 3(2x + 3) \times \dfrac{3(x - 7)}{2x - 5}$

Combine all factors into a single fraction.

$= \dfrac{9(2x - 5)(x + 3)(2x + 3)(x - 7)}{(x - 7)(2x + 3)(2x - 5)}$

Rearrange terms and separate fractions to see what simplifies.

$= \dfrac{9(x + 3)}{1} \times \dfrac{2x - 5}{2x - 5} \times \dfrac{2x + 3}{2x + 3} \times \dfrac{x - 7}{x - 7}$

Cancel each pair of equal factors in the numerator and denominator.

$= \dfrac{9(x + 3)}{1}$

Simplify.

$= 9(x + 3)$

Answer 2

Answer:

idk how you answer that

Step-by-step explanation: I am only in 8th grade sooooooooo yeah but i do help people by aking my teachers during school