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Zielflug [23.3K]
3 years ago
11

Hamlet cut a piece of paper into a rhombus to use as part of a costume. The piece of paper is shown below.*Picture not drawn to

scaleWhat is the area of the piece of paper? A. 44 square inches B. 60.5 square inches C. 105.6 square inches D. 121 square inches
Mathematics
1 answer:
ehidna [41]3 years ago
6 0
The answer is letter “B”
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11b-12<-100
ruslelena [56]

Answer:

ok wait which symbol? this (<)?

well it should stay the same since -100 is greater than the 11b-12

LHS=RHS

11b÷11b b must cancell b also do the same on -12. -12÷11 will give u a lesser value compared to -100

prove me wrong

4 0
3 years ago
Read 2 more answers
The sum of two numbers is -30. The difference of the two numbers is 18. What are the two numbers?
Vitek1552 [10]
The two numbers are -6 and -24
3 0
2 years ago
Matthew purchased a desk that was on sale for 45% off the orginal price of $480.If the sales tax was 8% (of the sale price), how
Yanka [14]

Answer:

285.12

Step-by-step explanation:

discount amount = 45/100 x 480= 45x48/10

=216.0

price after discount= 480-216=264

sales tax= 8/100 x 264=21.12

total money spent = 264+21.12=285.12

3 0
3 years ago
Read 2 more answers
Janice is considering two restaurants for a party. The first restaurant charges $15 per person plus a flat rate of $175 to reser
yan [13]

Answer:

The answer is 15x + 175 = 9x + 329.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0
3 years ago
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