Question

50. A bag contains five yellow tickets numbered one to five. The bag also contains five green tickets numbered one to five. You randomly pick a ticket. It is green or has a number greater than four. Find the probability of this occuring. (2.0 Points)

Answer 1

Answer:

60%

Step-by-step explanation:

There is a one in two chance of picking up a green ticket, since there are only two colours. The only number greater than 4 in this pack is 5. The chances of picking up a five are 2 out of 10. The chances of picking up a green 5 is 1 out of 10.

These events aren't mutually exclusive, because you can pick up a green 5 , which would constitute both events.

The probability of an OR function of events which aren't mutually exclusive is as follows:

$P(A or B) = P(A) + P(B)-P(A and B).$

Where:

A: green card

B: number 5 card

C: number 5 green card.

Thus:

$P(A or B)=\frac{5}{10} +\frac{2}{10} -\frac{\frac{x}{y} 1}{10} \\\\P(A or B)=\frac{6}{10} =0.6$