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Lilit [14]
3 years ago
8

If we draw lines to join each given point to the origin, identify the points whose corresponding line has a slope that is an int

eger value.

Mathematics
2 answers:
kozerog [31]3 years ago
6 0

Answer:

Brown circle red circle and blue circle

Step-by-step explanation:

xz_007 [3.2K]3 years ago
3 0

Answer:

The slopes of OA, OB ans OC are integer values.

Step-by-step explanation:

If a line passing through two points then the slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}

If one point is origin then the slope of the line is

m=\frac{y_2-0}{x_2-0}=\frac{y_2}{x_2}

The slope of line OA is

m_{OA}=\frac{8}{2}=4

It is an integer.

The slope of line OB is

m_{OB}=\frac{9}{3}=3

It is an integer.

The slope of line OC is

m_{OC}=\frac{8}{4}=2

It is an integer.

The slope of line OD is

m_{OD}=\frac{8}{5}

It is not an integer.

The slope of line OE is

m_{OE}=\frac{7}{6}

It is not an integer.

The slope of line OF is

m_{OF}=\frac{6}{7}

It is not an integer.

Therefore the slopes of OA, OB ans OC are integer values.

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Step-by-step explanation:

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now we can construct the sequence as follows:

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