If we draw lines to join each given point to the origin, identify the points whose corresponding line has a slope that is an int

Question

3 years ago

8

eger value.

2 answers:

kozerog [31] · Answer 1 · 2022-03-06T18:16:59+03:00

6 0

Answer:

Brown circle red circle and blue circle

Step-by-step explanation:

xz_007 [3.2K] · Answer 2 · 2022-03-06T16:56:09+03:00

Answer:

The slopes of OA, OB ans OC are integer values.

Step-by-step explanation:

If a line passing through two points then the slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}$

If one point is origin then the slope of the line is

$m=\frac{y_2-0}{x_2-0}=\frac{y_2}{x_2}$

The slope of line OA is

$m_{OA}=\frac{8}{2}=4$

It is an integer.

The slope of line OB is

$m_{OB}=\frac{9}{3}=3$

It is an integer.

The slope of line OC is

$m_{OC}=\frac{8}{4}=2$

It is an integer.

The slope of line OD is

$m_{OD}=\frac{8}{5}$

It is not an integer.

The slope of line OE is

$m_{OE}=\frac{7}{6}$

It is not an integer.

The slope of line OF is

$m_{OF}=\frac{6}{7}$

It is not an integer.

Therefore the slopes of OA, OB ans OC are integer values.