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Lilit [14]
3 years ago
8

If we draw lines to join each given point to the origin, identify the points whose corresponding line has a slope that is an int

eger value.

Mathematics
2 answers:
kozerog [31]3 years ago
6 0

Answer:

Brown circle red circle and blue circle

Step-by-step explanation:

xz_007 [3.2K]3 years ago
3 0

Answer:

The slopes of OA, OB ans OC are integer values.

Step-by-step explanation:

If a line passing through two points then the slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}

If one point is origin then the slope of the line is

m=\frac{y_2-0}{x_2-0}=\frac{y_2}{x_2}

The slope of line OA is

m_{OA}=\frac{8}{2}=4

It is an integer.

The slope of line OB is

m_{OB}=\frac{9}{3}=3

It is an integer.

The slope of line OC is

m_{OC}=\frac{8}{4}=2

It is an integer.

The slope of line OD is

m_{OD}=\frac{8}{5}

It is not an integer.

The slope of line OE is

m_{OE}=\frac{7}{6}

It is not an integer.

The slope of line OF is

m_{OF}=\frac{6}{7}

It is not an integer.

Therefore the slopes of OA, OB ans OC are integer values.

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<u>Solution:</u>

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\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}

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\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}

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