Step-by-step explanation:
dP/dt = -0.4P
Separate the variables and integrate.
dP/P = -0.4 dt
ln|P| = -0.4t + C
P = Ce^(-0.4t)
Use initial condition to find C.
2 = C^(0)
C = 2
P = 2e^(-0.4t)
dQ/dt = -1
Integrate.
Q = -t + C
Use initial condition to find C.
3 = 0 + C
C = 3
Q = -t + 3
Set the two equal.
2e(-0.4t) = -t + 3
Use a calculator to find t.
t = 2.156
The populations have the same size after 2.156 hours.
![\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%28x-2%29%28x%2B3%29%7D%7B2x%2B2%7D%5Cimplies%20%5Ccfrac%7Bx%5E2%2Bx-6%7D%7B2x%2B2%7D~~%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cleftarrow%20%5Ctextit%7B2nd%20degree%20polynomial%7D%5C%5C%20%5Cleftarrow%20%5Ctextit%7B1st%20degree%20polynomial%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvertical%20asymptote%7D%7D%7B2x%2B2%3D0%7D%5Cimplies%202x%3D-2%5Cimplies%20x%3D-%5Ccfrac%7B2%7D%7B2%7D%5Cimplies%20x%3D-1)
when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.
quick note:
when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.
Answer:
i need to see the plane please
Step-by-step explanation:
Answer:
Step-by-step explanation:
If you meant f(x) = √x - 1, then the domain is [0, infinity).
If you meant f(x) = √(x-1), then the domain is [1, infinity).
When any ambiguity may rear its ugly head, use parentheses, as indicated here.
Answer:41
Step-by-step explanation:
