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3 years ago

Find the vertical and horizontal asympotote for (×-2) (×+3)/ (2×+2)

1 answer:

6 0

$\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1$

when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.

quick note:

when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.

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124 = 14 - 6x + 3x + 5

Fittoniya [83]

$124 = 14 - 6x + 3x + 5$

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4 years ago

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Lcm of 1,2,12,30,84,165

cricket20 [7]

Answer:

$LCM(1,2,12,30,84,165)=2^2*3*5*7*11*1=4620$

Step-by-step explanation:

To find the LCM of 1,2,12,30,84,165 you must first find the prime factors of 12,30,84 and 165

12| 2 30| 2 84| 2 165| 3

6 | 2 15 | 3 42| 2 55 | 5

3 | 3 5 | 5 21 | 3 11 | 11

1 1 7 | 7 1

$12=2^2*3$ $30=2*3*5$ $84=2^2*3*7$ $165=3*5*11$

Now we look for common and uncommon factors with their greatest exponent

LCM(1,2,12,30,84,165)

Common factors with their greatest exponent: $2^2*3*5$

Uncommon factors with their greatest exponent: $7*11*1$

$LCM(1,2,12,30,84,165)=2^2*3*5*7*11*1=4620$

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4 years ago

F(x) = x^2. What is g(x)?

ladessa [460]

Answer:

-x²-2

Step-by-step explanation:

x² = the curve faces upwards

but

-x² the curve faces downwards.

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the downward curve touches -2 on the y axis.

therefore gx = -x²-2

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3 years ago

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Answer:

Step-by-step explanation:

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Given: <2 and <4 are vertical angles.

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∠2 ≅ ∠4

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4 years ago