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3 years ago

Find the vertical and horizontal asympotote for (×-2) (×+3)/ (2×+2)

1 answer:

6 0

$\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1$

when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.

quick note:

when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.

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How much would it have rained each month if the total amount of rain

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Answer:1.09090909091

Step-by-step explanation:

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3 years ago

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What is 1248x16=______<br>Guys please help <br>Have a good one!

AfilCa [17]

Answer:

19968

Step-by-step explanation:

Use the distributive property-

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3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

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3 years ago

What is the value of the expression (x-y)2 when x=5 and y=-1

rodikova [14]

(5- -1)2
(5+1)2
6x2
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3 years ago

2. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, o

Ugo [173]

Alright,

(a) 2x+4(x-1)=2
2x+4x-4=2---- Distrubution of 4(x-1)
6x-4=2---- Combining like terms
6x=6---- Making -4 equal 0 by adding +4 to both sides
x=1---- Divide the coefficiant (6)

(b) 25-x=15-(3x+10)
25-x=15-3x-10----Distribute the -1
25-x=5-3x---- Combine like terms
25=5-2x---- Make -x equal 0 by adding +x to both sides
20=-2x---- Make 5 equal zero by subtracting 5 (or adding -5) to both sides
-10=x---- Divide by the coefficiant (-2)

(c) 4x= 2x+2x+5(x-x)
4x=2x+2x+5(0)---- Distribute. Alright this might look hard but realy it is 1x-1x so the answer is 0
4x=2x+2x---- 5 times 0 is 0
4x=4x---- Combine like terms
x=x ---- divide by the coefficiant

Alright! Hope this helps! ;)

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3 years ago