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damaskus [11]
3 years ago
8

For what valuels of x is the equation |4x + 2| = x + 8 TRUE?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
5 0

Answer:

x=-2\quad \mathrm{or}\quad \:x=2

Step-by-step explanation:

|4x + 2| = x + 8 \\\\\mathrm{For\:each\:absolute\:find\:positive\:and\:negative\:intervals}\\\\\mathrm{Solve\:the\:inequality\:for\:each\:interval:}\\\\\mathrm{For\:}x

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Step-by-step explanation:

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Solve and explain how you got the answer :
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3 years ago
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MissTica
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4 0
3 years ago
Read 2 more answers
Find the number of real zeros of
Amiraneli [1.4K]

Answer:

B

Step-by-step explanation:

Using the determinant to determine the type of zeros

Given

f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct zeros

• If b² - 4ac = 0 then 2 real and equal zeros

• If b² - 4ac < 0 then 2 complex zeros

Given

f(x) = (x - 1)² + 1 ← expand factor and simplify

     = x² - 2x + 1 + 1

    = x² - 2x + 2 ← in standard form

with a = 1, b = - 2, c = 2, then

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Since b² - 4ac < 0 then the zeros are complex

Thus P(x) has no real zeros

6 0
3 years ago
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