THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
Answer:
b
Step-by-step explanation:
Well remember this:
When the signs are the same it is positive
When the signs are different make it negative
When you are subtracting a negative and positive, it is going to be like adding
for example:
-9 - 5 = -14
You just add 9 and 5 to get 14, the signs are different so it is going to be negative. ONLY WHEN YOU ARE SUBTRACTING NEGATIVES
Answer:
3 packages
Step-by-step explanation:
each package has 3
if she buys 1, she has 3 party favors
buys 2, has 6
buys 3, has 9
she can't buy 2 packages, then one friend doesn't get a party favor. so she will have to buy 3 packages, use 7, leave 2 extra.
please give thanks :)