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Talja [164]
3 years ago
10

A 160-lb man carries a 5-lb can of paint up a helical staircase that encircles a silo with radius 20 ft. If the silo is 90 ft hi

gh and the man makes exactly three complete revolutions, how much work is done by the man against gravity in climbing to the top
Mathematics
1 answer:
zheka24 [161]3 years ago
5 0

Weight of man and paint = 160 + 5 = 165 total pounds.

Gravitational force is independent of the path taken so we can ignore the radius of the silo.

Work done = total weight x height

The problem says he climbs to the top so overall height is 90 feet

Work = 165 lbs x 90 ft = 14,850 ft-lbs

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blsea [12.9K]

Answer:

20

Step-by-step explanation:

8/2=4

The workers were split in half, so the hours would go up:

10*2=20

I hope you understand what I mean...

                                                     :)

6 0
3 years ago
Find the attached question.​
inessss [21]

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Solution given:

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again

<C=<B[inscribed angle is half of the central angle]

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5 0
2 years ago
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kolbaska11 [484]
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3 years ago
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DerKrebs [107]

Answer:

see explanation

Step-by-step explanation:

note that f ○ g = f(g(x))

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In the same way

g ○ f = g(f(x))

To evaluate substitute x = 5x - 8 into g(x)

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3 0
3 years ago
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Answer:

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5 0
2 years ago
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