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Marrrta [24]
2 years ago
14

Do anyone know the answer to this? Answers please?

Mathematics
1 answer:
Amanda [17]2 years ago
5 0

Answer:

Yes

Step-by-step explanation:

You can check whether the ratios form a proportion, by setting one piece of the ratios as x

Thus, we can use the equation 4/3.2=22/x.

From this, we get 4x=70.4.

Solving for x gives us 17.6.

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Write three different integer addition expressions that equal –5.
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1. 5 + (-10)

2. -8 + 3

3. -7 + 2

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the answer is B.angle A and angle B

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How do you write 37 divided 3 distributive porperty
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37 divided by 3 = 12.333333333.....

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Step-by-step explanation:

4 0
2 years ago
Hayley has 383 beads. She buys 49 more beads. She will use 78 beads to make bracelets and the rest to make necklaces. She will u
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44 necklaces rounded up (or 44.25)
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3 years ago
Read 2 more answers
when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f
LenaWriter [7]

Answer:

Rs 120.  

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

8 0
2 years ago
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