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Eddi Din [679]
3 years ago
9

What is the equivalent to 2

Mathematics
1 answer:
algol133 years ago
5 0

Answer:

There are no choices on your question

Step-by-step explanation:

Maybe 2/1 or 4/2 or 10/5.

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Select the question that is different from the other three.
dlinn [17]
yup and your going to jail :)
3 0
3 years ago
Angles of a polygon <br>thanks ♡♡♡♡​
FinnZ [79.3K]

Answer:

900 degrees

Step-by-step explanation:

The sum of the interior angles of a polygon can be found by

(n-2)*180 where n is the number of sides

This figure has 7 sides

(7-2)*180

5*180

900

7 0
3 years ago
Jacky spent 53% of all her money to buy a computer game. How much did the game cost, if Jacky had $120 before buying the game?
Keith_Richards [23]
The game cost 63.6$, because 53% of 120 is 63.6
5 0
3 years ago
Read 2 more answers
Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
irinina [24]

Answer:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0
4 years ago
A triangular clock has sides measuring 16 cm, 12 cm, and 20 cm. What is the area to the nearest square centimeter?
kirza4 [7]

Answer:

96

Step-by-step explanation:

7 0
3 years ago
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