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Brrunno [24]
2 years ago
13

If EF=2x−12, FG=3x−15, and EG=23, find the value of FG

Mathematics
1 answer:
bixtya [17]2 years ago
5 0

Answer:

FG= 15

Step-by-step explanation:

2x-12+3x-15=23

5x-27=23

-27+27 23+27

5x=50

5x/5=50/5

x=10

FG= 3x-15

3(10)-15

30-15

FG=15

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The area of a circle is 28.26 square centimeters. What is its diameter (use 3.14 for ð)?
horsena [70]
Area for circle is  πr² so πr² =28.26 and we can sub 3.14 as pi
3.14*r²=28.26 we can divide by 3.14 to get r² on it's own
r²=28.26/3.14
then we root both sides to get r on it's own
28.26/3.14=9 √9=3
and the diameter is double the radius 3*2=6 so the diameter is 6

5 0
2 years ago
Solve for d<br> s = n /2 [ 2 a + ( n − 1 ) d ]
ludmilkaskok [199]

The answer is d= -2an+2s/n^2-n

That answer should be in a fraction form.

7 0
3 years ago
Write these numbers from least to greatest -0.615, -5/8, -0.62
inna [77]
Well -5/8 as a decimal would be -0.625.
So, the order would be -0.615 -0.62(0) and then -5/8 (or -0.625).
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5 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
2 years ago
at the city museum child admission is $5.10 and adult admission is $9.60. on thursday 132 tickets were sold for a total sale of
Bad White [126]
C + a = 132.....a = 132 - c
5.10c + 9.60a = 898.20

5.10c + 9.60(132 - c) = 898.20
5.10c + 1267.20 - 9.60c = 898.20
5.10c - 9.60c = 898.20 - 1267.20
-4.50c = - 369
c = -369/-4.50
c = 82 <=== child tickets sold
5 0
3 years ago
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