Answer:
(a) ðz/ðt = 1500miles/hr
(b) 10minutes
Step-by-step explanation:
Let x rep plane one
Let y rep plane two
ðx/ðt = 1440miles/hr = speed of plane one
ðy/ðt = 420miles/hr = speed of plane 2
ðz/ðt = ? = rate of change of distance btw two plane moving at right angle to meet at point o...
See attachment
Since x² + y² = z²... equation 1
So therefore (240² + 70²) ^½= z = 250 miles = distance between two planes
Differential rate of equation 1 gives
(2x* ðx/ðt ) + (2y* ðy/ðt) = 2z* ðz/ðt
Substituting to get ðz/ðt
(2*240*1440) + (2*70*420) = 2*250*ðz/ðt
750000 = 500 ðz/ðt
ðz/ðt = 1500miles/hr
B.
Since v = d/t where d = distance = 250miles
t = time = ? = time needed for controller to divert one of e planes , v = 1500miles/hr
t = d/v = 250/1500 = 10minutes
Answer:
b = 20
Step-by-step explanation:
The computation is shown below
Given that
24+ 6b > 138
where
b = 10
b = 15
b = 20
So if we take b = 10
= 24 + 6(10)
= 24 + 60
= 84
B = 15
= 24 + 6(15)
= 24 + 90
= 114
B = 20
= 24 + 6 (20)
= 24 + 120
= 144
So if we take b = 20 the inequality would be true
Answer: y = 85 2) 36.222°
Step-by-step explanation:
281 + 268 + 225 + 290 = 1064
1064 / 7 = 152
152 x 12 = 1824
392 + 512 + 413 + 422 = 1739
1824 - 1739 = 85
Therefore y = 85
Answer: (-2,1) (-5,0) (-1,-4) are the cooridents for the reflection
Step-by-step explanation: