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hoa [83]
3 years ago
13

F(x)=(+1)(x-3)(x-4)

Mathematics
1 answer:
zheka24 [161]3 years ago
7 0

Answer:

Step-by-step explanation:

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In circle J with m ∠ H L K = 42 m∠HLK=42, find the m ∠ H J K m∠HJK.
NARA [144]

Answer:

82

Step-by-step explanation:

All honesty I did 2*42=82 :) <3

5 0
2 years ago
If an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years? Round the answer to the n
Lilit [14]

Answer:

35.34 atoms will be present after 14,325 years.

Step-by-step explanation:

Given : Carbon-14 has a half-life of approximately 5,730 years. This exponential decay can be modeled with the function N(t) = N0. If an organism had 200 atoms of carbon-14 at death.

To find : How many atoms will be present after 14,325 years?

Solution :

The half-life exponential function modeled is N=N_o(\frac{1}{2})^{\frac{t}{h}}

Where, N_o=200 is the initial atoms

N is the total number of atoms.

t=14,325 years is the time  

h=5,730 years is the half-life time

Substitute the value in the formula,

N=200(\frac{1}{2})^{\frac{14325}{5730}}

N=200(\frac{1}{2})^{2.5}

N=200(0.1767)

N=35.34

Therefore, 35.34 atoms will be present after 14,325 years.

3 0
3 years ago
Biking at 10 mph, it takes Kristen 1/2 hour to reach the train station to go to work. Kristen then takes the train to work, and
Ket [755]

Answer:

17

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Given: R=2m
mr_godi [17]

Answer:

V = \frac{2L\sqrt{3}}{3} \pi}

A = 4\pi +  \sqrt{3L^{2} + 16}

Step-by-step explanation:

Figure of cone is missing. See attachment

Given

Radius, R = 2m

Let L = KL=LM=KM

Required:

Volume, V and Surface Area, A

<u><em>Calculating Volume</em></u>

Volume is calculated using the following formula

V = \frac{1}{3} \pi R^{2} H

Where R is the radius of the cone and H is the height

First, we need to determine the height of the cone

The height is represented by length OL

It is given that KL=LM=KM in triangle KLM

This means that this triangle is an equilateral triangle

where OM = OK = \frac{1}{2} KL

OK = \frac{1}{2}L

Applying pythagoras theorem in triangle LOM,

|LM|² =  |OL|² + |OM|²

By substitution

L² = H² + ( \frac{1}{2}L)²

H² = L² -  \frac{1}{4}L²

H² = L² (1 -  \frac{1}{4})

H² = L² \frac{3}{4}

H² = \frac{3L^{2} }{4}

Take square root of bot sides

H = \sqrt{\frac{3L^{2} }{4}}

H = \frac{L\sqrt{3}}{2}

Recall that V = \frac{1}{3} \pi R^{2} H

V = \frac{1}{3} \pi 2^{2} * \frac{L\sqrt{3}}{2}

V = \frac{1}{3} \pi * 4} * \frac{L\sqrt{3}}{2}

V = \frac{1}{3} \pi} * {2L\sqrt{3}}

V = \frac{2L\sqrt{3}}{3} \pi}

in terms of \pi an d L where L = KL = LM = KM

<u><em>Calculating Surface Area</em></u>

Surface Area is calculated using the following formula

H = \frac{L\sqrt{3}}{4}

A=\pi r(r+\sqrt{h^{2} +r^{2} } )

A=\pi * 2(2+\sqrt{((\frac{L\sqrt{3}}{2})^{2} +2^{2} } ))

A=\pi * 2(2+\sqrt{{\frac{3L^{2}}{4} } + 4 } )

A=\pi * 2(2+\sqrt{{\frac{3L^{2}+16}{4} } })

A=2\pi(2+\sqrt{{\frac{3L^{2}+16}{4} } })

A = 2\pi (2 + \frac{\sqrt{3L^{2} + 16}}{\sqrt{4}} )

A = 2\pi (2 + \frac{\sqrt{3L^{2} + 16}}{2} )

A = 2\pi (2 + {\frac{1}{2} \sqrt{3L^{2} + 16})

A = 4\pi +  \sqrt{3L^{2} + 16}

6 0
3 years ago
Mr. Pham mowed 2/7 of his lawn. his son mowed 1/4 of the lawn who mowed the most? How much of the lawn still needs to be mowed
liubo4ka [24]
The answer is 2/7, so Mr. Pham
8 0
2 years ago
Read 2 more answers
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