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3 years ago

15 is what percent of 56

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

4 0

15 is 26.7857% of 56

Masja [62]3 years ago

3 0

Fifteen is 26.79% of fifty six

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5 times the complement of an angle is 15 more than two times the supplement of the angle. Find the angle,

USPshnik [31]

Answer:

The angle measures 25°; the complement measures 65°; the supplement measures 155°.

Step-by-step explanation:

The sum of the measures of two complementary angles is 90.

If the angles measure x and y, then x + y = 90.

Given angle x, then y = 90 - x.

The sum of the measures of two supplementary angles is 180.

If the angles measure x and y, then x + y = 180.

Given angle x, then y = 180 - x.

Let the angle be x.

Its complement is 90 - x.

Its supplement is 180 - x.

5(90 - x) = 2(180 - x) + 15

450 - 5x = 360 - 2x + 15

-3x = -75

Angle: x = 25

Complement: 90 - x = 90 - 25 = 65

Supplement: 180 - x = 180 - 25 = 155

Answer: The angle measures 25°.;, the complement measures 65°; the supplement measures 155°.

8 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Which measurement is most accurate to describe the amount of water a teaspoon could hold?

dybincka [34]

Your answer is A.) 5mL

7 0

3 years ago

What is the polynomial 3y2 + (y + 7)2 – 15 after it has been fully simplified and written in standard form?

Greeley [361]

Answer:

4y^2 + 14y + 34

I hope this helps :)

4 0

3 years ago

Change x^2-2x-3 to intercept form

Stella [2.4K]

The answer u have is correct how it is

7 0

3 years ago