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Anit [1.1K]
4 years ago
12

Help please! Thank you!

Mathematics
1 answer:
a_sh-v [17]4 years ago
6 0
1. The 3 angles form a straight angle which is equal to 180 degrees.
2.  Alternate interior angles formed by parallel lines and a transversal are congruent.
3.  Same as 2
4.  m∡A + m∡2 + m ∡ C = 180
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A scientist measures the width of ten different tree branches in inches. The results were 18, 24, 27, 30, 21, 18, 24, 30, 30, an
arlik [135]
The mode is the number that occurs most frequently in the set.
Putting the numbers in order will help us find the mode.
18,18,21,24,24,24,27,30,30,30

We see that 24 and 30 have an equal number of occurrences in the data set, meaning that 24 and 30 are both modes.
3 0
4 years ago
Solve -2x+5y-9 when y=1
bija089 [108]
Hello there.

<span>Solve -2x+5y-9 when y=

Just c</span><span>ombine like terms
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</span>=<span><span>−<span>2x</span></span>−<span>3</span></span>
5 0
4 years ago
The fundraising group collected the quarters from the school's wishing well. The group arranged the quarters into 8 piles and of
Mariulka [41]
8•20=q. Multiply the number of piles by the number of quarters in each pile: 8•20=160, there were 160 quarters. Now to find how much they made multiply the number of quarters by how much 1 quarter is: 160•.25=40 they made $40 :)
7 0
3 years ago
A line passes through the two given points. Is it vertical , horizontal , or neither ?
TiliK225 [7]
Well to give your question an answer the points (as i have graphed them) seem to have the same Y axis. This means that a horizontal line can pass through the points. Horizontal: In geometry, a horizontal line is one which runs from left to right across the page. It comes from the word 'horizon', in the sense that horizontal lines are parallel<span> to the horizon.</span>

4 0
4 years ago
Find the volume of the following solid. Using cylindrical coordinates
Reika [66]

In cylindrical coordinates, the equations of the surfaces become

z = 4 - 4r^2 \\\\ z = (r^2)^2 - 1 = r^4 - 1

These surfaces intersect on the cylinder of radius 1 with cross sections parallel to the x,y-plane:

4 - 4r^2 = r^4 - 1 \\\\ \implies r^4 + 4r^2 - 5 = (r-1)(r+1)(r^2+5) = 0 \\\\ \implies r=1

Then in cylindrical coordinates, the volume of the space bounded by these surfaces is

\displaystyle \int_0^{2\pi}\int_0^1\int_{r^4-1}^{4-4r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^1 \int_{r^4 - 1}^{4-4r^2}r\,\mathrm dz\,\mathrm dr \\\\ = \pi \int_0^1 (4-4r^2)^2 - (r^4-1)^2 \,\mathrm dr \\\\ = \pi \int_0^1 (15-32r^2+18r^4-r^8)\,\mathrm dr = \boxed{\frac{352\pi}{45}}

7 0
3 years ago
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