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Damm [24]
3 years ago
14

Which angles are corresponding angles?Check all that apply.​

Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0

Answer: Options 'A', 'C' and 'F' are correct.

Step-by-step explanation:

Since we have given that

Corresponding angles are those angles which takes the same corresponding position at intersection when a transversal cut the two parallel lines.

so, According to this , we get that

∠1 and ∠5

∠2 and ∠6

∠3 and ∠7

∠4 and ∠8

so, Options 'A', 'C' and 'F' are correct.

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kvasek [131]

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3 0
3 years ago
Read 2 more answers
The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 . a.
Anastasy [175]

Answer:

a) 0.073044

b) 0.75033

c) The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

Step-by-step explanation:

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 .

a. Find the probability that an individual distance is greater than 218.00 cm.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 218

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

For x > 218

z = 218 - 205.5/8.6

z = 1.45349

Probability value from Z-Table:

P(x<218) = 0.92696

P(x>218) = 1 - P(x<218) = 0.073044

b. Find the probability that the mean for 15 randomly selected distances is greater than 204.00

When = random number of samples is given, we solve using this z score formula

z = (x-μ)/σ/√n

where

x is the raw score = 204

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

n = 15

For x > 204

Hence

z = 204 - 205.5/8.6/√15

z = -0.67552

Probability value from Z-Table:

P(x<204) = 0.24967

P(x>204) = 1 - P(x<204) = 0.75033

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

3 0
3 years ago
What plus what equals -8 ?
Vinil7 [7]

Answer:

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Step-by-step explanation:

3 0
2 years ago
If c(x) = 4x-2 and d(x) = x^2 + 5x is is (c•d) (x)
FinnZ [79.3K]
<h3>Answer: (c * d)(x) = 4x^3 + 18x^2 - 10x</h3>

Work Shown:

I'm assuming the dot means multiplication. If so, then,

(c * d)(x) = c(x)*d(x)

(c * d)(x) = [ c(x) ] * [ d(x) ]

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(c * d)(x) = 4x^3 + 20x^2 - 2x^2 - 10x

(c * d)(x) = 4x^3 + 18x^2 - 10x

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4 0
3 years ago
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