What is 6.9×10^7 written in standard form
2 answers:
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Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this
So, i integrate this,
I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
So, i integrate this,
I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
Answer:
The sampling distribution is, p = center = 0.043
The standard deviation of the sample, s = 6.0015×10⁻⁴
The shape is normal
Step-by-step explanation:
Here we have the standard deviation of a sample proportion, given by the following relation;
The center = p = 4.3% or 0.043
The shape is found by the value of n×p hence;
114250 × 0.043 = 4912.75 > 10 and
n(1 - p) = 114250 × (1 - 0.043) = 109337.25 also > 10 hence the shape is normal.