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Tju [1.3M]
3 years ago
6

Find the 30th term of the arithmetic sequence with a first term of 4 and a comman difference of 8 ​

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

236

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 4 and d = 8, thus

a_{30} = 4 + (29 × 8) = 4 + 232 = 236

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Step-by-step explanation:

<u>Given:</u> ΔABC,

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3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

m\angle A+m\angle ADC+m\angle ACD=180^{\circ}\\ \\50^{\circ}+90^{\circ}+m\angle ACD=180^{\circ}\\ \\m\angle ACD=180^{\circ}-50^{\circ}-90^{\circ}=40^{\circ}

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m\angle ACD+m\angle BCD=m\angle ACB\\ \\40^{\circ}+m\angle BCD=85^{\circ}\\ \\m\angle BCD=85^{\circ}-40^{\circ}=45^{\circ}

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so

m\angle A+m\angle ACB+m\angle B=180^{\circ}\\ \\50^{\circ}+85^{\circ}+m\angle B=180^{\circ}\\ \\m\angle B=180^{\circ}-50^{\circ}-85^{\circ}=45^{\circ}

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<span>Which two measures did the United States take to counter terrorism after the September 11 attacks?

</span>
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