2 years ago

The center of a circle is at (2 -5) and it's radius is 12. What is the equation of the circle?

Mathematics

1 answer:

hichkok12 [17]2 years ago

8 0

Answer:

144

Step-by-step explanation:

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Use the quadratic formula to solve the equation

azamat

Answer:

Step-by-step explanation:

12−5+6=0

using the Quadratic Formula where

a = 1, b = -5, and c = 6

=−±2−4‾‾‾‾‾‾‾‾√2

=−(−5)±(−5)2−4(1)(6)‾‾‾‾‾‾‾‾‾‾‾‾‾‾√2(1)

=5±25−24‾‾‾‾‾‾‾√2

=5±1‾√2

The discriminant 2−4>0

so, there are two real roots.

Simplify the Radical:

=5±12

=62=42

which becomes

hope this helps :)

7 0

2 years ago

If p(x)=x^2+x+1 and q(x)=3x^2-1, find p(7)

Delvig [45]

Answer:

p(7) = 57

Step-by-step explanation:

Because this is a function, all you have to do is input 7 for x like so:

p(x)=x^2+x+1 ---------------> p(7)=7^2+7+1

so 49 + 8

= 57

7 0

2 years ago

12=x÷8<br> I need help please

Simora [160]

Answer:

x=96

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the result of adding these two equations?

kicyunya [14]

Well the total would be -5

6 0

2 years ago

Please help <br> solve for x

Nuetrik [128]

Answer:

Step-by-step explanation:

ACB is an inscribed angle

so ∠ACB = 1/2 mAB

Hence we got

$4x+4=\frac{1}{2}. 96 \\4x+4=48\\4x=44\\x=11$

4 0

3 years ago

Read 2 more answers

The center of a circle is at (2 -5) and it's radius is 12. What is the equation of the circle?​

The center of a circle is at (2 -5) and it's radius is 12. What is the equation of the circle?