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lilavasa [31]
2 years ago
7

The center of a circle is at (2 -5) and it's radius is 12. What is the equation of the circle?​

Mathematics
1 answer:
hichkok12 [17]2 years ago
8 0

Answer:

144

Step-by-step explanation:

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What property justifies this statement
Varvara68 [4.7K]

Answer:

B. SUBTRACTION PROPERTY OF EQUALITY

Step-by-step explanation:


4 0
3 years ago
Complete the chart to find the mean,variance,and standard deviation. 45 340 400 825
hoa [83]

Answer:

<u>A. Mean =  402.5</u>

<u>B. Variance = 77,556.25</u>

<u>C. Standard Deviation =  278.49</u>

Step-by-step explanation:

Let's calculate the mean, variance and standard deviation of the set of numbers given:

A. Mean = (45 + 340 + 400 + 825)/4 = 1,610/4 =<u> 402.5</u>

B. Variance [(45 - 402.5)² + (340 - 402.5)² + (400 - 402.5)² + (825 - 402.5)²]/4 =  [(127,806.25 + 3,906.25 +6.25 + 178,506.25/4 =<u> </u><u>77,556.25</u>

C. Standard Deviation = √Variance = √77,556.25 =<u> 278.49</u>

7 0
3 years ago
ANSWER ME SWEET JESUS
Pepsi [2]

Answer:

Part A: 36%

Part B: It is repeating because it is infinite

Step-by-step explanation:

16 / 44 = 0.36363636...

5 0
3 years ago
An irregular polygon is shown below: Image of irregular polygon with length of 7 units and height of 3 units labeled on left sid
torisob [31]
I don’t see the image can you please add one to the comments so I can answer it. Thanks
7 0
2 years ago
find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i
tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
  • L = length of incline = 100 ft and
  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

brainly.com/question/25970931

#SPJ1

3 0
1 year ago
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