Answer: an audio file containing speech
Explanation:
Answer:
C. 220.100.100.45 to 220.100.100.46
Explanation:
The Classless IP subnetting of 220.100.100.0 begins from the fourth octet of the IP address. To get 45 subnet mask, it uses 6 bits from the fourth octet, which approximately give 64 subnets, while the remaining 2 bits are used for host IP addressing.
The useable host IP addresses are gotten from the formula '
-2', with n=2 bits.
useable host IP addresses = 2^2 - 2 = 2 addresses per subnet.
While the 12th subnet is 12 x 2^2 = 44.
This means that the 12th subnet mask starts with 220.100.100.44 (as the network address) and ends with 220.100.100.47 as broadcast IP address, while '.45' and '.46' are the assignable addresses of the subnet.
// making the class
class Counter {
int counter;
int limit;
// Constructor
Counter(int a, int b){
counter = a;
limit = b;
}
// static function to increment
static increment(){
if(counter<limit)
nCounter+=1;
}
// Decrement function
void decrement(){
if(counter>0)
nCounter-=1;
}
int getValue(){
return counter;
}
static int nCounter;
int getNCounters(){
return nCounter;
}
};
// Initializa the static
int Counter::nCounter = 0;
the ip nat inside source command to link the inside local and inside global addresses
I hope this helps! :)
Answer:
The complete method is as follows:
public List buildList(List L)
{
L.insert(30);
L.insert(23);
L.insert(19);
L.insert(4);
return L;
}
Explanation:
To complete the method, we make use of the insert() function.
This inserts elements of the list into list L. However, we have to start from the last element (i.e. in descending order)
So, the explanation is as follows:
L.insert(30); --- This inserts the last element
Continue inserting in descending order
<em> L.insert(23); </em>
<em> L.insert(19);
</em>
Until the first list element is inserted
L.insert(4);
This returns the filled list L
return L;
