Question

BEST ANSWER GETS BRAINLIEST!! HELP PLEASE.

Answer 1

Answer:

$\text{The area of parallelogram is }8 ft^2$

$\text{The area of two triangles of equal area is }4 ft^2$

Step-by-step explanation:

Given a parallelogram ABCD is shown with DC equal to 9 feet and the perpendicular distance between AB and DC equal to 8 over 9 foot.

Part A: we have to find the area of ABCD.

$\text{Area of parallelogram=}Base\times height$

$=9\times \frac{8}{9}=8 ft^2$

$\text{The area of parallelogram is }8 ft^2$

Part B:

We have to decompose this parallelogram into two triangles.

Join diagonal AC

As the diagonal of parallelogram divides it into two congruent triangles of equal area

Hence, the area of each triangle is

$\frac{1}{2}ar(ABCD)$

$\frac{1}{2}\times 4=4 ft^2$

$\text{The area of two triangles of equal area is }4 ft^2$