Answer:
<h3>
Acute Angles: ∠TLS, ∠SLT, ∠ULR</h3><h3>
Right Angles: ---------</h3><h3>
Obtuse Angles: ∠RLT, ∠SLU, ∠ULS,</h3><h3>
Straight Angles: ∠RLS, ∠TLU </h3><h3>
Not angles: ∠TRL </h3>
Step-by-step explanation:
The lines intersect at point L, so all angles have a vertex (middle letter) L so there is no angle TRL
Straight angle is a line with dot-vertex, so the straight angles are ∠RLS and ∠TLU.
∠TLS is less than 90° then it is acute angle (∠SLT is the same angle). ∠ULR is vertex angle to ∠TLS, so it's also acute angle.
Two angles adding to straight angle mean that they are both right angles or one is acute and the second is obtuse. ∠TLS is acute so ∠RLT is obtuse (they adding to ∠RLS) and ∠SLU is obtuse (they adding to ∠TLU). ∠ULS is the same angle as ∠SLU.
Answer:
7:21
Step-by-step explanation:
Lcm(9,12)=9*4=36 minutes later
That is
6:45+36min=7:21
Answer:
I think it's 9:50
Step-by-step explanation:
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
Answer:
H0 : mu1 = mu2
Ha : mu1 ≠ mu2
Which means
Null hypothesis H0; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is the same/equal
Alternative hypothesis Ha; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is different (not equal)
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean(i.e it tries to prove that the old theory is true). While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
Therefore, for the case above;
H0 : mu1 = mu2
Ha : mu1 ≠ mu2
Which means
Null hypothesis H0; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is the same/equal
Alternative hypothesis Ha; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is different (not equal)