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xz_007 [3.2K]
3 years ago
15

Emily made 14 out of 19 shots during basketball practice. About what percent of her shots did she make? Explain your reasoning

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0
Approximately <span>%73.684210526</span>
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“if the same strength and direction Of force is exerted on 2 objects, why might they be affected differently?” Answer journal #7
Ulleksa [173]

Answer:

If one is larger, there will be less stress on the middle of the object

Step-by-step explanation:

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3 years ago
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En el pequeño frasco se colocaron 7 galletas para regalar si ornearon 56 ¿cuantos frascos. regalaron?​
Solnce55 [7]

Answer:

1 frasco

Step-by-step explanation:

En el pequeño frasco se colocaron 7 galletas para regalar si ornearon 56 ¿cuantos frascos. regalaron?

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I need help plz whats 6=-w/8 i ned to find w and show work but im very confused
inysia [295]
6= w/8
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3 years ago
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What is the surface area of this rectangular pyramid?
Alexxx [7]

Answer:

304m^2

Step-by-step explanation:

First find the surface area of the base by multiplying the length by the width.

(12m) (8m)= 96m^2

Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.

1/2 (12m) (10m)= 60m^2

Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.

1/2 (8m) (11m)= 44m^2

Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.

base=a, front/ back triangles= b, side triangles=c

SA= a + 2b +2c  or SA= a +b +b +c +c

Using one of the equations above solve for the total surface area.

SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)

or

SA= (96m^2) + 2(60m^2) +2(44m^2)

SA=  (96m^2) +(120m^2) +(88m^2)

SA= 304m^2

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3 years ago
Log 16 1 = x solve for x
Helga [31]

Answer:

x = Log(16)

Simplify both sides of the expression by isolating the variable.

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