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AnnZ [28]
3 years ago
7

Find the zero when f(x)=3x-12

Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer:

\mathrm{Axis\:interception\:points\:of}\:3x-12:\quad \mathrm{X\:Intercepts}:\:\left(4,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-12\right)

\mathrm{X\:Intercepts}:\:\left(4,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-12\right)

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A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa
g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8 \times h + 5 \times f = 24

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6 \times h + 2 \times f = 16.60

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

<h3>h = 2.5</h3>

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

<h3>f = 0.8</h3>

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0
3 years ago
A rectangle is 1/3 yd long and 2/3 yd wide
ICE Princess25 [194]
It might be 2/9 sorry if it wasn’t
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3 years ago
Find the area and perimeter of the shape below. Show your work.
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Area= 10.8m Perimeter= 15.6m hope this helps
4 0
3 years ago
Identify the types of number ​
zysi [14]

Answer:

1 surds

2 fraction

3 decimal

4 negative

5 positive

5 0
3 years ago
Read 2 more answers
You have a box that is a good size for your tape collection. two rows of tapes will fit in the box. the box is 10 inches wide. e
jeyben [28]

Solution:

Two rows of tapes will fit in the box.

Box wide = 10 inches

Each tape wide = 5/8 inches

10/ (5/8) = (10 * 8)/5

= 16

There are two in each row. So, 32 tapes will fit in the box.


3 0
3 years ago
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