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AnnZ [28]
3 years ago
7

Find the zero when f(x)=3x-12

Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer:

\mathrm{Axis\:interception\:points\:of}\:3x-12:\quad \mathrm{X\:Intercepts}:\:\left(4,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-12\right)

\mathrm{X\:Intercepts}:\:\left(4,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-12\right)

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Simplify -12x + 5x. <br> -7 <br> -7x<br> -17x
Leno4ka [110]
7x. Try to ignore the X's for a second and think of the problem as -12+5 (aka 5-12). The answer to that is 7. now add the x back again to get: 7x
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What is 1.15​% of 26​?
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Answer:0.299

Step-by-step explanation:

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Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. In the first part of the race, her av
s344n2d4d5 [400]

Nikita's distance from her for the second part of the race was 1.5 kilometers.

Since Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand, and in the first part of the race, her average speed was 8.75 kilometers per hour, while for the second part of the race, she started to get tired, so her average speed dropped to 6 kilometers per hour, to determine which expression represents Nikita's distance for the second part of the race the following calculation must be performed:

  • 8.75 x 0.65 + 6 x 0 = 5.68
  • 8.75 x 0.50 + 6 x 0.15 = 5.275
  • 8.75 x 0.40 + 6 x 0.25 = 5
  • 100 = 60
  • 40 = X
  • 40 x 60/100 = X
  • 24 = X
  • 39 - 24 = 15
  • 15 = 1/4 hour
  • 6/4 = 1.5

Therefore, Nikita's distance from her for the second part of the race was 1.5 kilometers.

Learn more about maths in brainly.com/question/22791791

6 0
2 years ago
Tamara has decided to start saving for spending money for her first year of college. Her money is currently in a large suitcase
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Add both of the function together.

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3 years ago
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Jayden has some dimes and some quarters. He has at most 25 coins worth at least $4.60 combined. If Jayden has 7 dimes, determine
Y_Kistochka [10]

Answer:

Step-by-step explanation:

A dime is worth 10 cents. Converting to dollars, it becomes 10/100 = $0.1

A quarter is worth 25 cents. Converting to dollars, it becomes 25/100 = $0.25

Let x represent the number of dimes that Jayden has.

Let y represent the number of quarters that Jayden has.

Jayden has some dimes and some quarters. He has at most 25 coins. It means that

x + y ≤ 25

The coins worth at least $4.60 combined. It means that

0.1x + 0.25y ≥ 4.6 - - - - - - - - - - 1

If Jayden has 7 dimes, then

7 + y ≤ 25

y ≤ 25 - 7

y ≤ 18

Substituting x = 7 into equation 1, it becomes

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0.25y ≥ 3.9

y ≥ 3.9/0.25

y ≥ 15.6

All possible values for the number of quarters that he could have would be

15.6 ≤ y ≤ 18

6 0
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