Answer:
Please Find the solution below
Step-by-step explanation:
Let us say the two equations are
x+y=5 --------------(A)
x-y=1 -------------(B)
Let us solve them for x and y by adding them
2x=6
x=3
Hence from (A)
3+y=5
y=2
Hence our solution is
x=3, y=2
Adding same number to equation (A) say 2 we get
x+y+2=5+2
x+y=5+2-2
x+y=5
Hence equation remains the same while adding same number to each side.
Same thing happens if we add same number to equation (B)
Hence we draw the conclusion that the solution remains the same if same number is added to each side of the original equation.
4(3w+5)-2w=70
10w+20=70
10w+20-20=70-20
10w=50
10w/10=50/10
w=5
Answer: 
Step-by-step explanation:
You know that 1 sandwich costs $4.60 and the school bought 47 sandwiches.
Therefore, in order to calculate the total cost of 47 sandwiches, you need to multiply this number of sandwiches bought by the schoole, by the cost of 1 sandwich. Then:

You know that 1 bag of chip costs $1.25 and the school bought 39 bags of chips.
So, in order to calculate the total cost of 39 bags of chips, you must multiply the total number of them bought by the school, by the cost of 1 bag of chips.
Then:
Therefore, the total amount school spent was:

Answer:
If -pi/3, the answer would be -1.05. If positive pi, then it's 1.05.
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