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3 years ago

. What is the coefficient of the xy-term in the expression 4x+5xy–2y?

Mathematics

1 answer:

quester [9]3 years ago

8 0

Answer: 5

Step-by-step explanation:

The coefficent for the xy term is 5. This is because the number attached to the term xy is 5.

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Write the subtraction expression for the number line shown.

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Answer is

0-4-9

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3 years ago

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Can anybody help me plzzzz

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2 years ago

Tawny has 2 1/2 pints of juice. She has glasses that can hold 5 fluid ounces. How any glasses can she fill with juice?

Oduvanchick [21]

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3 years ago

Each answer choice below represents a relation by a set of ordered pairs. In which of the answer choices is the relation a funct

alexdok [17]

Answer:

A - Not Function

B - Function

C - Function

D - Not Function

E - Function

Step-by-step explanation:

For a relation to be a function, each value of input should have exactly one output. Which means that for one value of x, there should only one value of y. If the relation has repetition of x in its ordered pairs, it means that for one value of x, there are two or more values of y, hence the relation is not a function

(Consult the diagram below)

As x = 6 is being repeat, it means that x=6 has two values of y that are 12 and 4. IT IS NOT A FUNCTION.

No repetition of x, IT IS A FUNCTION.

No repetition of x, IT IS A FUNCTION.

As x = -1 is being repeat, it means that x=-1 has two values of y that are 4 and -2. IT IS NOT A FUNCTION.

No repetition of x, IT IS A FUNCTION.

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3 years ago

You bicycle along a straight flat road with a safety light attached to one foot. Your bike moves at a speed of 15 km/hr and your

Viefleur [7K]

Answer:

x(t) = ( 4.167 t + 0.2 cos (2πt))

y(t) = ( 0.3 - 0.2 sin (2πt))

b) the foot have to be 3.32 rev/sec faster

Step-by-step explanation:

Given that:

the speed of the bike = 15 km/hr = 15 × 1000/3600 (m/sec) = 4.167 m/sec

radius of the circle when the foot moves = 20 cm = 0.2 m

radius of the circle above the ground = 30 cm = 0.3 m

Let assume that:

x(t) should represent the vector along the horizontal moment

y(t) should be the vector along the vertical moment

The initial component will be ( 0, 0.3)

We know that the radius of the circle is given as 0.2 m, So the vector of the circle can be written as (0.2 cos t , 0.2 sin t )

Also, the foot makes one revolution in a second, definitely the frequency of the revolution = 1 and the vector for the circle is ( 0.2 cos (2πt), -0.2 sin (2πt)), due to the fact that the foot moves clockwise.

Thus, adding all the component together ; we have:

(x(t), y(t)) = (0,0.3)+(4.167 t , 0)+(0.2 cos (2πt), -0.2 sin (2πt))

(x(t), y(t)) = (4.167 t + 0.2 cos (2πt), 0.3 - 0.2 sin (2πt))

Hence; the parametric equations are:

x(t) = ( 4.167 t + 0.2 cos (2πt))

y(t) = ( 0.3 - 0.2 sin (2πt))

The linear speed of rotation is :

15km/hr = 15 × 100, 000/3600 (cm/sec)

= 416.7 cm/sec

The rotational frequency is :

= 416.7/2πr

= 416.7/2(3.14 × 20)

= 3.32 rev/sec

Hence, the foot have to be 3.32 rev/sec faster in rotating if an observer standing at the side of the road sees the light moving backward.

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3 years ago

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