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lianna [129]
3 years ago
13

How do I factor out a constant before factoring out a quadratic? Factor completely: 3w^2-3w-90

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0
3w^2-3w-90 =0 \ \ \:3 \\ \\w^2- w-30 =0 \\ \\a=1 , \ b= -1 , c= -30 \\ \\\Delta =b^2-4ac = (-1)^2 -4\cdot1\cdot (-30) =1+120=121 \\ \\w_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2 }=\frac{ 1-11}{2}=\frac{-10}{2}=-5

w_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2 }=\frac{ 1+11}{2}=\frac{12}{2}=6 \\ \\ Answer:\\ \\ w^2- w-30 =(x+5)(x-6)
 

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Step-by-step explanation:

If ABC is a right triangle, where the right angle is B, then

  • The hypotenuse of the triangle is b and a , c are its legs
  • sin(A) = \frac{a}{b}
  • sin(C) = \frac{c}{b}
  • b=\sqrt{a^{2}+c^{2}}
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∵ ABC is a right triangle

∵ m∠C = 90°

∴ c is the hypotenuse and a , b are its legs

∵ m∠A = 58.3°

- The sum of the two acute angles in the right triangle = 90°

∴ m∠A + m∠B = 90°

- Substitute the measure of angle A

∴ 58.3 + m∠B = 90

- Subtract 58.3 from both sides

∴ m∠B = 31.7°

∵ sin(A) = \frac{a}{c}

∵ c = 24.8 feet

∴ sin(58.3) = \frac{a}{24.8}

- By using cross multiplication

∴ a = (24.8) × sin(58.3)

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∴ sin(31.7) = \frac{b}{24.8}

- By using cross multiplication

∴ b = (24.8) × sin(31.7)

∴ b = 13.0 ft

m∠B = 31.7° , a = 21.1 ft , b = 13.0 ft

Learn more:

You can learn more about solving the triangle in brainly.com/question/12985572

#LearnwithBrainly

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