Answer:
A = 340 adult.
C = 398 children.
Step-by-step explanation:
Let the number of children be C
Let the number of adults be A
Translating the word problem into an algebraic equation, we have;
A + C = 738 .......equation 1
1.5C + 2C = 1306 .......equation 2
A = 738 - C .......equation 3
Substituting eqn 3 into eqn 2, we have;
1.5(738 - C) + 2C = 1306
1107 - 1.5C + 2C = 1306
1306 - 1107 = 2C - 1.5C
199 = 0.5C
C = 199/0.5
<em>C = 398 children. </em>
Now, to find the value of A.
From equation 3;
A = 738 - C
A = 738 - 398
<em>A = 340 adult. </em>
The GCF of 72 and 36 is: 36
List out the factors of each number (72 and 36), and find the common factors between the two numbers.
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
Looking at the factors above, the common ones are 1, 2, 3, 4, 6, 9, 12, 18, and 36. But... considering we are looking for the "greatest" common factor, our highest number out of the listed ones is 36, making it the greatest common factor of 72 and 36.
Answer:
88
Step-by-step explanation:
you just multiply base by height
Answer:
They will be 170 miles apart at 10 AM
Step-by-step explanation:
Nancy has 15´ of head start which is 1/4 hr.
NHD = 20*(1/4) = 5 miles is her head start
Mark leaves at 7.15hs = starting point
Marks stop at when they are 170 miles apart = t
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t = the time they are 170 miles apart
d= distance in miles Nancy travels in time t
170 - (d+5) = distance in miles Mark travels in time t
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Nancy's equation:
(1) d = 20t
Mark's equation:
(2) 170 - (d+5) = 40t
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(2) 170-d-5=40t
(2) d+40t=165
Substitute (1) into (2)
(2) 20t+40t=165
(2) 60t=165
(2) t=2.75
7:15 AM + 2.75 hrs (2:45hs) = 10 AM
They are 170 miles apart at 10 AM
check:
(1) d=20t
(1) d=20*2.75
(1) d=
55
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(2) 170 - (d+5) = 40t
(2) 170 - (d+5) = 40*2.75
(2) 170 - d-5 = 110
(2) d=55
