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Ganezh [65]
1 year ago
13

Use the discriminant, b2 - 4ac, to determine which equation has complex solutions.

Mathematics
1 answer:
ruslelena [56]1 year ago
3 0

Using the discriminant, the quadratic equation that has complex solutions is given by:

x² + 2x + 5 = 0.

<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>

A quadratic equation is modeled by:

y = ax² + bx + c

The discriminant is:

\Delta = b^2 - 4ac

The solutions are as follows:

  • If \mathbf{\Delta > 0}, it has 2 real solutions.
  • If \mathbf{\Delta = 0}, it has 1 real solutions.
  • If \mathbf{\Delta < 0}, it has 2 complex solutions.

In this problem, we want a negative discriminant, hence the equation is:

x² + 2x + 5 = 0.

As the coefficients are a = 1, b = 2, c = 5, hence:

\Delta = 2^2 - 4(1)(5) = 4 - 20 = -16

More can be learned about the discriminant of quadratic functions at brainly.com/question/19776811

#SPJ1

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Take the last digit of the number, double it and subtract it to the remaining number, if the result is multiple of 7, then the initial number is a multiple of 7.

In this case the last digit is 0, so when we double it and subtract it, we actually are not changing the other 3 digits.

Then we have that:

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The next option is 998, we can do the same here:

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994, such that:

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So we have 137 multiples of 7 with 3 digits.

Then we have 137 4-digit numbers, that end with a zero and also are divisible by 5 and 7.

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