So, how far is the car from where it was at t = 0 is 40 m
<h3>Velocity of the car</h3>
Since the location x of the car in meters is given by the function x = 30t - 5t² where t is in seconds, we need to find the time at which its velocity is 10 m/s in the negative direction by differentiating x with respect to t to find its velocity, v.
So, v = dx/dt
= d(30t - 5t²)/dt
= d30t/dt - d5t²/dt
= 30 - 10t
When v is 10 m/s in the negative direction, v = -10 m/s.
So, v = 30 - 10t
-10 = 30 - 10t
-10 - 30 = -10t
-40 = -10t
t = -40/-10
t = 4 s
<h3>The distance at 4 s when its velocity is -10 m/s</h3>
Since at t = 4 s, its velocity is -10 m/s and x = 30t - 5t² is the car's location. The car's distance from t = 0 after its velocity is -10 m/s is
x(4) - x(0) = 30(4) - 5(4)² - [30(0) - 5(0)²]
= 120 - 5(16) - [0 - 0]
= 120 - 80 - 0
= 40 m
So, how far is the car from where it was at t = 0 is 40 m
Learn more about distance of car here:
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Answer:
the answer is B
Step-by-step explanation:
Answer:
y= 6/5x -8
Step-by-step explanation:
The slope-intercept form (basically the form for the equation of a line)
y=mx+b
m is the slope
x is the value you want to plug in, or the x term in a point (x, y)
we know so far,
y=6/5x + b
so to find the missing value let's plug in the x & y value from (5, -2) and use the given slope
-2 = 6/5(5) + b
6 / 5 x 5/1 or 6/5 times 5 is 30/5 or 6
so
-2 = 6 + b
subtract 6 from each side to isolate the b value or y-intercept ( the point on the graph that is on the y-axis)
-8 = b
Answer: Capacity of Marshfield Stadium is 109,015 and capacity of Bowden is Bowden.
Step-by-step explanation:
Let x = Capacity of Marshfield Stadium.
y = Capacity of Bowden.
As per given, we have
x - y = 7,675 (i)
x+y = 210,355 (ii)
2x = 218030 (iii)
Put value of x in (i) , we get
109015 - y = 7675
⇒ y= 109015 - 7675
⇒ y= 101,340
Hence, capacity of Marshfield Stadium is 109,015 and capacity of Bowden is Bowden.
