Answer:
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Step-by-step explanation:
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Answer:
Yuhh the answers c dawhggg trus me i just did the same thing lawl!
Step-by-step explanation:
Answer:
Step-by-step explanation:
The solution is in the attached file
Answer:
30 mph
Step-by-step explanation:
Let d = distance (in miles)
Let t = time (in hours)
Let v = average speed driving <u>to</u> the airport (in mph)
⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)
Using: distance = speed x time
Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:
We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:
Now all we have to do is solve the equation for v:
As v is positive, v = 30 only
So the average speed driving to the airport was 30 mph
(and the average speed driving from the airport was 45 mph)
TW x WU = CW x VW
Fill in the known values:
WU = TU - TW = 21.2 - 14.6 = 6.6
14.6 x 6.6 = 6 x VW
Simplify:
96.36 = 6VW
Divide both sides by 6:
VW = 96.36 / 6
VW = 16.06
Round to one decimal place:
VW = 16.1
The answer is D>