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Oliga [24]
3 years ago
9

A motorboat left a harbor and traveled to an island at an average rate of 13 knots. The average speed on the return trip was 10

knots. If the total trip took 6.9 hours, how far is the harbor from the island?
Mathematics
1 answer:
vlada-n [284]3 years ago
4 0

Answer:

The distance between harbor & the island D = 72.12 km

Step-by-step explanation:

Let the total distance between harbor & island = D

Motor boat going to the island at speed S_{1} = 13 knots = 24 \frac{km}{hr}

Return speed of the motorboat S_{2} = 10 knots = 18.52 \frac{km}{hr}

The total time taken for both journey = 6.9 hours

\frac{D}{S_{1} } + \frac{D}{S_{2} } = 6.9

\frac{D}{24} + \frac{D}{18.52} = 6.9

D (\frac{1}{24} + \frac{1}{18.52} ) = 6.9

D ( 0.0956 ) = 6.9

⇒ D = 72.12 km

This is  the distance between harbor & the island.

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Look at this graph:
amm1812

For the given graph , slope of the line is equal to  ( 1 / 2 ).

As given in the question,

Form the given graph,

Scale is given by,

On x-axis each unit of the graph represent 1 unit.

On y- axis each unit of the graph represent 1 unit.

Consider two coordinates from the line of the graph,

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brainly.com/question/3605446

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Hi can someone please help me? :( im not sure where im going wrong. ty!!
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The triangle ABC is a right angled triangle , right angled at C because it is the angle subtended by the diameter

Now OA = OB = OC = 4 cm (radii)

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